Answer:
<h2>11.4</h2>Solution,
∆ ACB = ∆ EFD
finding the value of X,
Apply cross product property
Calculate the product
Divide both sides by 5
Calculate
Hope this helps...
Good luck on your assignment...
The scatter plot shows a regression line of advertising dollars spent and sales. If the company were to spend $6,500 on advertis
ing, what would be the predicted sales?
A) $110,000
B) $114,000
C) $118,000
D) $122,000
HELPPP PLEASE IM GIVING OUT BRAINLIEST
A) $110,000
B) $114,000
C) $118,000
D) $122,000
HELPPP PLEASE IM GIVING OUT BRAINLIEST
1 answer:
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Answer:
The minimum income level for this target group is of $51,253.6.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of $41,182 and a standard deviation of $11,990
This means that
Find the minimum income level for this target group.
The 100 - 20 = 80th percentile, which is X when Z has a p-value of 0.8, so X when Z = 0.84.
The minimum income level for this target group is of $51,253.6.