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denis-greek [22]

3 years ago

8

What final exam grade would you need in order to get a 73% in the class if the other averages are as follows? (PLEASE JUST HELP

ME OUT!!!)
Quizzes: 92%
Midterm: 65%
Knewton: 87%
Worksheets: 74%
Labs: 81%
Project: 89%
Final ??

Grading
Quizzes: 10%
Midterm: 30%
Knewton: 5%
Worksheets: 5%
Labs: 15%
Projects: 5%
Final exam: 30%

1 answer:

oksano4ka [1.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

Letter Grade Percentage GPA

B- 80-82 % 2.7

C+ 77-79 % 2.3

C 73-76 % 2.0

C- 70-72 % 1.7

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Complete the solution of the equation. Find the

forsale [732]

Answer:

y = -2

Step-by-step explanation:

Put x as -19 and solve for y.

2(-19) - 5y = -28

Multiply.

-38 - 5y = -28

Add 38 on both sides of the equation.

-5y = -28 + 38

-5y = 10

Divide both sides by -5.

y = 10/-5

y = -2

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3 years ago

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Use the following graph of the function f(x) = 2x3 + x2 − 3x + 1 to answer this question: graph of 2x cubed plus x squared minus

Zina [86]

Answer:

7

Step-by-step explanation:

f(x) = 2x^3 + x^2 − 3x + 1

f'(x) = 6x^2 + 2x − 3

The slope at -2:

f'(-2) = 6(-2)^2 + 2(-2) − 3

f'(-2) = 24 + -4 − 3

f'(-2) = 17

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The slope at 0:

f'(0) = 6(0)^2 + 2(0) − 3

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The average rate of change is (17+(-3))/2, or 14/2, or 7

6 0

2 years ago

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Kilo typed 1,125 words in 15 minutes let w represent the number of words typed each minute If Lolo typed the same number of word

Alborosie

Answer:

She type <u>75 words</u> in 1 minute.

Step-by-step explanation:

Given:

Lolo typed 1,125 words in 15 minutes.

Let w represent the number of words typed each minute.

Now, to find the number of words she type in 1 minute if Lolo typed the same number of words each minute.

So, we solve it by using cross multiplication method:

<u><em>As 1125 words is equivalent to 15 minutes.</em></u>

<u><em>Thus, w number of words equivalent to 1 minutes</em></u>.

$\frac{1125}{15} =\frac{w}{1}$

By cross multiplying we get:

⇒ $1125=15w$

<em>Dividing both sides by 15 we get:</em>

⇒ $75=w$

⇒ $w=75.$

Therefore, she type 75 words in 1 minute.

4 0

3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

So

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

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3 years ago

Kevin finished a race in 25.7 minutes juile finished the race 7 1/10 sooner than kevin finished it how many minutes did it take

Papessa [141]

Answer:

18.6 minutes

Step-by-step explanation:

subtract. im sorry if this is not right. im not smart

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3 years ago