The probability that a randomly selected customer will wait more than 4 minutes at the deli is given below
- The probability that a randomly selected customer will wait more than 4 minutes =
![0.4286](https://tex.z-dn.net/?f=0.4286)
The waiting time for the customers is uniformly distributed between 0 - 7 minutes
Consider a random variabe X that represents the waiting time of customers and uniformly distributed between 0-7 minutes
Therefore, the density function of X is determined as
![f(x) = \frac{1}{b-a}\\\\f(x) = \frac{1}{7-0}\\\\f(x) = \frac{1}{7}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cfrac%7B1%7D%7Bb-a%7D%5C%5C%5C%5Cf%28x%29%20%3D%20%5Cfrac%7B1%7D%7B7-0%7D%5C%5C%5C%5Cf%28x%29%20%3D%20%5Cfrac%7B1%7D%7B7%7D)
The probability that the customer will wait more than 4minutes,
![P(X>4) = \int\limits^7_4 f{x} \,dx\\\\= \int\limits^7_4 \, \frac{1}{7}dx\\\\= \frac{1}{7} * [x]^7_4\\\\= \frac{7-4}{7} \\\\= 0.4286](https://tex.z-dn.net/?f=P%28X%3E4%29%20%3D%20%5Cint%5Climits%5E7_4%20f%7Bx%7D%20%5C%2Cdx%5C%5C%5C%5C%3D%20%5Cint%5Climits%5E7_4%20%20%5C%2C%20%20%20%5Cfrac%7B1%7D%7B7%7Ddx%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B7%7D%20%2A%20%5Bx%5D%5E7_4%5C%5C%5C%5C%3D%20%5Cfrac%7B7-4%7D%7B7%7D%20%5C%5C%5C%5C%3D%200.4286)
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Answer:
4
Explanation:
Since it's a flippy number, we can set each digit into ababa
Since it can be divisible by 15, which means it can be divisible by both 5 and 3.
Since it is divisible by 5, the last digit will be either 0 and 5, but it cannot be 0 because 0 cannot be the first digit, so last digit must be 5.
So, ababa --> 5b5b5
It can also be divisible by 3. According to de divisibility rule of 3, if the sum of all digit is divisible by 3 then the number is divisible by 3.
Sum of all digits = 15 + 2b
it's divisible by 3 when b = 0,3,6,9
The answer is 4.
There are 4 such number.
Answer: D
Explanation because there is no point in having to know other skills. that don't evolve your job.
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