Answer:
$\text{\underline{\textbf{Given values:}}}$ $\omega_0=0 \: \dfrac{\text{rad}}{\text{s}}$ $\omega_1=3000 \: \text{rpm}$ $t=2\: \text{s}$ First, we ...
Explanation:
The probability of choosing a puppy that is female and white from the given sample we have is; 25%
<h3>How to solve conditional probability?</h3>
The question asks for the probability that Ruby will randomly choose a puppy that is female and white. This is not mutually exclusive events or joint.
White female = 8 - (3 + 1 + 2)
White Female = 2 puppies
Mixed colored females = 3
White male = 1
Mixed colored male = 2
Total number of puppies = 8
Thus, the probability of choosing a puppy that is female and white is;
P(choosing a female puppy) = 2/8 = 1/4 = 25%
Complete question is;
Rubys dog has 8 puppies. the puppies include white females, 3 mixed color females, 1 white male, and 2 mixed color males. ruby wants to keep one puppy.what is the probability that she randomly chooses a puppy that is female and white
Read more about Conditional Probability at; brainly.com/question/23382435
(x+y)^2=56
x^2+2xy+y^2=56. we know that xy=12
so 2(xy)=24
x^2+24+y^2=56
x^2+y^2=56-24
x^2+y^2=32. <-------------
