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2 years ago

Plz helppp!!!!! I NEED IT NOWW !!!!!!!!!!!!!!!!

Mathematics

2 answers:

Sever21 [200]2 years ago

4 0

I think the answer is b have a great day sorry if I’m wrong also could I get brainliest

VashaNatasha [74]2 years ago

3 0

Answer:

We Them holler boys holler if you need and something don't holler if you need a chip on her shoulder or a high-end with a loaded gun will be out that screen door no shirt on leaving two black marks down the one-lane road yeah we yeah we yeah wheel am I

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before getting to school john has a few errands to run john has to walk 5 blocks to the galley and 9 blocks to the library befor

Serggg [28]

Answer:

9 blocks

Step-by-step explanation:

The total of what John has already walked and the number more he must walk will be equal to the number he has to walk to get to school.

12 + more = 5 + 9 + 7

more = 9 + 5 + 7 - 12 . . . . . subtract 12 from both sides

more = 9

John must walk 9 blocks more.

_____

We recognize that 5+7 = 12, so that last part of the sum totals zero.

6 0

2 years ago

Starting with x=4.62 repeating express x as a fraction in simplest form

arsen [322]

$x=4.62=4+0.62=4+\dfrac{62}{100}=4+\dfrac{62:2}{100:2}=4+\dfrac{31}{50}\\\\\text{as a mixed number}\ 4\dfrac{31}{50}\\\\\text{as an improper fraction}\ \dfrac{4\cdot50+31}{50}=\dfrac{231}{50}$

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3 years ago

On a number line, 9.7 would be located where? Choose all answers that make a true statement

RideAnS [48]

Answer:

Step-by-stepapex answer to the left of 9.9 and to the right of 9.3 explanation:

6 0

3 years ago

What number must you add to complete the square?<br> x^2 + 2x = -1

Andru [333]

$\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}$

$\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}$

If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

6 0

3 years ago

Read 2 more answers

7x+5(-6)=-9 solve for x

ElenaW [278]

Answer:

x=3

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers