now, we're making the assumption that the front and back of the tent are trapezoidal, Check the picture below.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ h=32\\ a=23\\ b=36.5 \end{cases}\implies \begin{array}{llll} A=\cfrac{32(23+36.5)}{2}\implies A=952 \\\\\\ \stackrel{\textit{twice that much}}{2A=1904} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20h%3D32%5C%5C%20a%3D23%5C%5C%20b%3D36.5%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B32%2823%2B36.5%29%7D%7B2%7D%5Cimplies%20A%3D952%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%3D1904%7D%20%5Cend%7Barray%7D)
Answer:
49.47
Step-by-step explanation:
Take what she started with and subtract what she ended with
428.25 - 378.78
49.47
This is the amount she spent
2 1/2 * 3
5/2 * 3/1
= 15/2
15/2 - 11 3/8
15/2 - 91/8
91/8 - 60/8
= 31/8 = 7 7/8
answer=7 7/8
Answer:
No extra pieces.
Step-by-step explanation:
Given:
Total number of foot board = 3
Equally divided into = 1/2
Question asked:
How many extra pieces will I have = ?
Solution:
By dividing 3 by 1/2 we can find the extra pieces.
= 
= 
= 
Since, the remainder is zero, thus there is no any extra pieces I have.
Answer:
∠NQP = 74°
Step-by-step explanation:
NPQ is a triangle.
We know the sum of 3 angles of a triangle is 180 degrees. So we can write:
N + P + Q = 180
2x + 34 + 2x + 2 = 180
Now, we can solve for x:

The measure of NQP is "2x+2", we plug in x = 36, and find the measure of NQP:
∠NQP = 2(36) + 2 = 74°