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Alex787 [66]
2 years ago
8

PLS HELP ASAP ILL GIVE BRAINLKEST THANKS

Mathematics
1 answer:
Julli [10]2 years ago
8 0

Answer:

D. (6,3)

Step-by-step explanation:

To the find which point can be located on the line you will have to find the point-slope form

The formula for point-slope form is y=mx+b

m is slope

b is y-intercept

Since we already know the slope we can just replace it:

y=1/2x+b

Now we need to find the y-intercept

We can do this by distributing them with (4,2)

As you remember in point the digits are in x and y

(x,y) so we can tell that 4 is x and 2 is y

Now we can substitute x with 4 and y with 2

2=1/2(4)+b

Multiply 1/2 and 4

which is 2

2=2+b

Thus b=0

So the slope intercept form is y=1/2x

Now we can substitute the other points:

For (5,2):

2=5/2

Which is incorrect since 2 does not equal 5/2

For (2,3):

3=1/2(2)

Which is

3=1

Which is incorrect since 3 does not equal 1

For (3,4)

4=1/2(3)

Which is

4=3/2

Which is incorrect since 4 does not equal 3/2

For (6,3)

3=1/2(6)

Which is

3=3

Which is correct since 3 does equal to 3

Hope this helps!

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Answer:

Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)

Step-by-step explanation:

This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.

First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.

Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.

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Step-by-step explanation:

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Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

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Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
3 years ago
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