Who is Pitagoras???????
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The question is incomplete. The complete question is :
Which expressions are equivalent to 3x+3(x+y)3x+3(x+y)3, x, plus, 3, left parenthesis, x, plus, y, right parenthesis ? Choose all answers that apply:
(Choice A) A 6x+3y6x+3y6, x, plus, 3, y
(Choice B) B 3(x+x+y)3(x+x+y)3, left parenthesis, x, plus, x, plus, y, right parenthesis
(Choice C) C 3xy3xy
Solution :
The equation is given as follows :
3x + 3(x+y)
We can simplify the equation in order to determine the equivalent expression.
Now applying the distributive property,
When we add the like terms we get :
3x+3x+3y = 6x + 3y
When we factor out the term 3, we get :
3x + 3x + 3y = 3(x + x + y)
So, the expressions in options (B) and (C) are equivalent to the expression 3x + 3(x + y).
Given that N is the incenter of △ABC, NS = 4.
<h3>What is the Incenter of a Triangle?</h3>- The incenter of a triangle is the point of concurrency of the three angle bisectors of a triangle.
- The perpendicular distances from each sides of the triangle to the incenter are equal.
Given the image where:
NQ = 2x
NR = 3x − 2
NQ = NR = NS (equidistant from the incenter)
Thus:
2x = 3x - 2
- Add like terms
2x - 3x = -2
-x = -2
x = 2
NQ = NS = 2x
- Plug in the value of x
NS = 2(2)
NS = 4
Therefore, given that N is the incenter of △ABC, NS = 4.
Learn more about the incenter on:
