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hichkok12 [17]
3 years ago
5

Evaluate y=x squared minus 2x plus one for 3i

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

- 8 - 6i

Step-by-step explanation:

The given expresion is

y =  {x}^{2}  - 2x + 1

We want to evaluate this expression when x=3i

We substitute to obtain:

y =  {(3i)}^{2}  - 2(3i) + 1

We simplify to get

y =  {3}^{2}  \times  {i}^{2}  - 6i + 1

Recall that

{i}^{2}  =  - 1

This implies that:

y = 9 \times  - 1 - 6i + 1

y =  - 9 - 6i + 1

y =  - 8 - 6i

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Find the equation of a line passing through the point(-3,0) and (2,-3)​
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Answer <u>(assuming the question allows it to be written in slope-intercept form)</u>:

y = -\frac{3}{5} x-\frac{9}{5}

Step-by-step explanation:

1) First, find the slope of the equation. Use the slope formula m = \frac{y_2-y_1}{x_2-x_1}, substitute the given points' x and y values, and simplify:

m = \frac{(-3)-(0)}{(2)-(-3)} \\m  =\frac{-3-0}{2+3}\\m = -\frac{3}{5}

Thus, the slope is -\frac{3}{5}.

2) Now, use the point-slope formula y-y_1 = m (x-x_1) and substitute real values for m, x_1, and y_1.

Since m represents the slope, substitute -\frac{3}{5} in its place. Since x_1 and y_1 represent the x and y values of a point the line crosses, use the x and y values of any one of the given points to substitute into the formula. (Either one is fine. I chose (2,-3).) Then, isolate y to put it into slope-intercept form and find the answer:

y-(-3) = -\frac{3}{5} (x-(2))\\y + 3 = -\frac{3}{5} x + \frac{6}{5} \\y = -\frac{3}{5} x - \frac{9}{5}

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3 years ago
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Help the math of mine plz
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(-267) - (-855)<br><br> I really need this but take your time
irinina [24]
-267 - (-855) is the same as
-267 + 855 or
855 - 267
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Hope this helped!
7 0
3 years ago
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