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hichkok12 [17]
3 years ago
5

Evaluate y=x squared minus 2x plus one for 3i

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

- 8 - 6i

Step-by-step explanation:

The given expresion is

y =  {x}^{2}  - 2x + 1

We want to evaluate this expression when x=3i

We substitute to obtain:

y =  {(3i)}^{2}  - 2(3i) + 1

We simplify to get

y =  {3}^{2}  \times  {i}^{2}  - 6i + 1

Recall that

{i}^{2}  =  - 1

This implies that:

y = 9 \times  - 1 - 6i + 1

y =  - 9 - 6i + 1

y =  - 8 - 6i

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