Answer:
29.69 m/s
Explanation:
From the question given above, the following data were obtained:
Height (h) = 45 m
Velocity (v) =...?
Next, we shall determine the time taken for the ball to get to the ground. This can be obtained as follow:
Height (h) = 45 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
45 = ½ × 9.8 × t²
45 = 4.9 × t²
Divide both side by 4.9
t² = 45/4.9
Take the square root of both side
t = √(45/4.9)
t = 3.03 s
Finally, we shall determine the velocity with which the ball hits the ground. This is illustrated below:
Initial velocity (u) = 0 m/s
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) = 3.03 s
Final velocity (v) =.?
v = u + gt
v = 0 + (9.8 × 3.03)
v = 0 + 29.694
v = 29.694 ≈ 29.69 m/s
Therefore, the ball hits the ground with a velocity of 29.69 m/s.
The velocity of sound in air is 358m/s
<h3>Calculations and Parameters</h3>
Given;
- Frequency= 256 Hz
- Water level= 30cm
- Position of resonance= 100cm
- The velocity of sound in air= ?
v= 2f(L2-L1)
= 2.2.56.(1- 0.3)
=358 m/s
Read more about velocity of sound in air here:
brainly.com/question/15211242
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Draw something similar to which has more mass in density. For example, a bowling ball and a volley ball. Both substances are similar in size but the bowling ball feels heavier than the volleyball. Label volleyball for less density and bowling ball with more density.
Answer:
The maximum force that can be applied without causing the two 43- kg crates to move is 2.7KN
Explanation:
Given data
μ coefficient of friction 0.31
mass of two crates =2*43kg
=86kg
Weight of the two crates =mg
Assuming g= 9.81m/s²
W =86*9.81= 843.66N
We know that force against friction is given by
W =μR
Where
μ is coefficient of static friction
R limiting force
To solve for let's make it the subject of the formula
R= W/μ
R=843.66/0.31
R= 2721.5N
R= 2.7KN
Most of the momentum is transferred to the ball on top. Since the collision in this situation is elastic, momentum is conserved, meaning the momentum of both balls before hitting the floor is equal to the momentum of both balls right after the collision.