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Softa [21]
3 years ago
7

9.46 Air enters the compressor of an ideal cold air-standard Brayton cycle at 100 kPa, 300 K, with a mass flow rate of 6 kg/s. T

he compressor pressure ratio is 10, and the turbine inlet temperature is 1400 K. For k 5 1.4, calculate (a) the thermal efficiency of the cycle. (b) the back work ratio. (c) the net power developed, in kW.
Physics
1 answer:
Colt1911 [192]3 years ago
8 0

Answer:

a) 67pa

Explanation:

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A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.
alex41 [277]

The magnitude of the unknown height of the projectile is determined as 16.1 m.

<h3>Magnitude of the height</h3>

The magnitude of the height of the projectile is calculated as follows;

H = u²sin²θ/2g

H = (36.6² x (sin 29)²)/(2 x 9.8)

H = 16.1 m

Thus, the magnitude of the unknown height of the projectile is determined as 16.1 m.

Learn more about height here: brainly.com/question/1739912

#SPJ1

3 0
2 years ago
A 50-g chunk of 80 degrees C iron is dropped into a cavity in a very large block of ice at 0 degrees C. Show that 5.5 g of ice w
Alenkasestr [34]

Answer:

5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

Explanation:

The concept to solve this problem is given by Energy Transferred, the equation is given by,

Q = mc\Delta T

Where,

Q= Energy transferred

m = mass of water

c = specific heat capacity

\Delta T = Temperature change (K or °C)

Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,

Q = mc\Delta T

Q = 50*0.11*(80-0)

Q = 440cal

Then we can calculate the heat absorbed by m grams of ice at 0°C, then

Q_2 = mL = 80*m

How Q_1=Q_2, so

80m=440

m=\frac{440}{80}

m = 5.5g

Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity

7 0
3 years ago
What did the results of photoelectric-effect experiment establish?
Bond [772]

Answer:

Thanks For Points Mark Me Brainliest Please

Explanation:

Electrons are emitted as soon as low-intensity, high-frequency light hits a metal surface.

A. Is It

7 0
3 years ago
Read 2 more answers
a body of a mass 1kg suspended from a spring is found to stretch the spring by 10cm. (A) what is the spring constant? what is pe
Nikitich [7]

Answer:

(A) The spring constant is <u>98 N/m.</u>

(B) The period of oscillation is <u>0.635 s.</u>

Explanation:

Given:

Mass of the body is, m=1\ kg

Extension length of the spring is, x=10\ cm=0.1\ m

Now, let 'k' be the spring constant.

The force acting on the body is due to gravity only and is equal to its weight.

So, weight of the body is given as:

F_g=mg\\F_g=1\times 9.8\\F_g=9.8\ N

Now, we know that for a spring-mass system, the net force acting on the body is equal to the product of the spring constant and extension length. Therefore,

F_g=kx\\9.8=k(0.1)\\k=\frac{9.8}{0.1}=98\ N/m

Hence, the spring constant is 98 N/m.

(B)

Period of oscillation of a body of spring-mass system in SHM is given as:

T=2\pi\sqrt{\frac{m}{k}}

Plug in the given values and solve for period 'T'. This gives,

T=2\pi\sqrt{\frac{1}{98}}\\T=2\pi\times 0.101\\T=0.635\ s

Therefore, the period of oscillation is 0.635 s.

5 0
3 years ago
You are trying to escape the potential impact area and head 500km south and then 400 km west. You see on the news that you haven
marusya05 [52]

Answer:

400

Explanation:

8 0
3 years ago
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