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tangare [24]
3 years ago
14

HELP PLEASE!!!!

Physics
1 answer:
mojhsa [17]3 years ago
3 0

Player 1 because they are the heaviest and therefore have more weight they have to stop from moving.

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27. Calculate the impulse when an average<br> force of 10 N acts on a cart for 5.0 s.
wlad13 [49]

Answer:

50 Ns

Explanation:

Impulse = force × time

J = F Δt

J = (10 N) (5.0 s)

J = 50 Ns

6 0
4 years ago
Is true that the earth's crust is made up of many tectonic plates?
RUDIKE [14]
Yes, it is true.<span> In the 20th century, researchers realized that the </span>Earth's crust<span> is not one piece, but is </span>made up of many<span> huge </span>tectonic plates<span> upon which the continents ride.</span>
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3 years ago
How to do this question
Yuki888 [10]

Answer:

64°

Explanation:

The triangle is an isosceles triangles (both legs are equal to the radius of the circle), so that means the base angles are the same.

Angles of a triangle add up to 180°, so:

128 + 2x = 180

2x = 52

x = 26

∠1 is complementary to the base angle, so:

∠1 = 90 − 26

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7 0
3 years ago
The attractive electrostatic force between the point charges +8.44 ✕ 10-6 and q has a magnitude of 0.961 n when the separation b
d1i1m1o1n [39]
The electrostatic force between two charges Q1 and q is given by
F=k_e  \frac{Q_1 q}{r^2}
where 
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Q1 is the first charge
q is the second charge
r is the distance between the two charges

Re-arranging the formula, we have
q= \frac{F r^2}{k_e Q_1}
and since we know the value of the force F, of the charge Q1 and the distance r between the two charges, we can calculate the value of q:
q= \frac{(0.961 N)(0.67 m)^2}{(8.99 \cdot 10^9 N m^2 C^{-2})(+8.44\cdot 10^{-6}C)}=5.69 \cdot 10^{-6} C

And since the force is attractive, the two charges must have opposite sign, so the charge q must have negative sign.
6 0
3 years ago
What is a point of view of an object used to determine another object's motion
Finger [1]
<h2><em>A reference point is a place or object used for comparison to determine if something is in motion. An object is in motion if it changes position relative to a reference point. You assume that the reference point is stationary, or not moving.</em></h2>
7 0
3 years ago
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