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tangare [24]
3 years ago
14

HELP PLEASE!!!!

Physics
1 answer:
mojhsa [17]3 years ago
3 0

Player 1 because they are the heaviest and therefore have more weight they have to stop from moving.

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trapecia [35]

Answer:

it is c

Explanation:

8 0
3 years ago
Assuming 100% efficient energy conversion, how much water stored behind a 50cm high hydroelectric dam would be required to charg
7nadin3 [17]

Answer:

12.245m3

Explanation:

The electric energy is created by The potential energy substended by the specific volume of water in dam.

Electric energy is calculated as

E= Q× V

E is Energy, Q is charge and V is Voltage

Note that this energy has been given and is 60Joules

From conservation of energy it means;

M× g×h = 60

Where M is the mass of water.

g is acceleration of free fall due to gravity which is 9.8m/S2

h is the height of water flow.

From change of subject of formula for M; we have:

M = 60/ g × h

= 60/ 9.8 × 0.5

= 12.245kg

Now how much water required means the volume of water;

Note density = mass/volume

Therefore volume = mass/density

=12.245/1= 12.245m3

Note the density of water is 1kg/m3

4 0
3 years ago
List five (5) compounds h2o can form (10 points)
Elena-2011 [213]

Oxygen, hydrogen, sodium, chlorine, lead, iron. Hope this helps!!!


8 0
3 years ago
If the distance of a charged particle from a wire changes from 10cm to 20 cm , what happens to its magnetic field
postnew [5]

Answer:

i would say it decreases

Explanation:

bc as distance grows the fields decrease

IM NOT SURE tho

5 0
3 years ago
Read 2 more answers
A rocket in deep space has an exhaust-gas speed of 2000 m/s. When the rocket is fully loaded, the mass of the fuel is five times
notka56 [123]

Answer:

 v_{f} = 1,386 m / s

Explanation:

Rocket propulsion is a moment process that described by the expression

       v_{f} - v₀ =  v_{r} ln (M₀ / Mf)

Where v are the velocities, final, initial and relative and M the masses

The data they give are the relative velocity (see = 2000 m / s) and the initial mass the mass of the loaded rocket (M₀ = 5Mf)

We consider that the rocket starts from rest (v₀ = 0)

At the time of burning half of the fuel the mass ratio is that the current mass is    

       M = 2.5 Mf

       v_{f} - 0 = 2000 ln (5Mf / 2.5 Mf) = 2000 ln 2

       v_{f} = 1,386 m / s

3 0
3 years ago
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