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tangare [24]
3 years ago
14

HELP PLEASE!!!!

Physics
1 answer:
mojhsa [17]3 years ago
3 0

Player 1 because they are the heaviest and therefore have more weight they have to stop from moving.

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A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi
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Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

           F_{net} = F_{1} + F_{2} = 0  

So,  

          \frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

      \frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}

On dividing both sides of the equation by G.m.M, we get the following.

      \frac{1}{(1 - x)^{2}} = \frac{3}{x^{2}}

               x^{2} = 3 - 6x + 3x^{2}

                    0 = 3 - 6x + 2x^{2}

Using the formula, \frac{-b \pm \sqrt{(b)^{2} - 4ac}}{2a}   the value of x comes out to be equal to +2.37 (not usabale) and -0.634 (usable).

Hence, we can conclude that the third mass will be located 0.634 meters away from the 3 m mass.

7 0
3 years ago
Match each key term with the correct definition.
oksano4ka [1.4K]

Answer:

Radioisotope -> An atom with an unstable nucleus

Radioactivity -> The spontaneous discharge of energy from an unstable nucleus

Radioactive Decay -> The process by which the nucleus of an unstable isotope changes

Strong Nuclear Force -> Binds protons and neutrons together in the nucleus

Explanation:

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Below is an attachment containing the solution to the question.

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There is a horizontal abduction and horizontal adduction in the transverse plane that is imaginary bisector that divides the body into two halves upper or top and lower or bottom halves.
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