Answer:
0.534
Step-by-step explanation:
p(0 losses) = 0.7² = 0.49
p(1 loss) = 2 x 0.3 x 0.7 = 0.42
p(2 losses) = 0.09
This is a conditional probability problem. If the number of people hospitalized is 0 or 1, then the total loss will be less than 1. However, if two people are hospitalized, the probability that the total loss will be less than 1 is 0.5. we need to exclude the 50% x 0.09 chance of a double loss costing more than 1. So
P(Cost < 1)
= 0.49 + 0.42 +0.045
= 0.955
P(0 losses | Cost < 1)
= P(0 losses and Cost < 1) / P(Cost < 1)
= 0.49 / 0.955 = 0.513
P(1 loss | Cost < 1)
= 0.42 / 0.955 = 0.440
P(2 losses | Cost < 1) = 0.045 / 0.955 = 0.047
Now take the expectation:
E[X] = (0)(0.513) + (1)(0.440) + (2)(0.047)
= 0.440 + 0.094
= 0.534
Answer:
-32
Step-by-step explanation:
you have to be in the negatives because 22 is bigger than 10.
Tip that will save you time:
when you have an equation like this just add the two numbers together and then add a negative sign :D
22+10= 32
-32
The answer to a8 of the sequence will be 8. I found this out by multiplying the subtraction value (.25) by the number in the sequence needed (8) to get 2. Then, I subtracted the starting number with 8 to get 8 (10-2 = 8). Hope this helped :)
Answer:
$40
Step-by-step explanation:
use y = mx + b
y = amount saved = ?
m = amount saved per week = $10
x = time (in months) saving = 2.5
b = money jerry started with = $15
plug in:
y = (10)(2.5)+15
y = $40
