first off, let's notice the graph touches the x-axis at -1 and 3, namely, those are the zeros/solutions/roots of the polynomial and therefore, the factors come from those points.
now, at -1, the graph doesn't cross the x-axis, instead it <u>simply bounces off</u> of it, that means the zero of x = -1, has an even multiplicity, could be 4 or 2 or 6, but let's go with 2.
at x = 3, the graph does cross the x-axis, meaning it has an odd multiplicity, could be 3 or 1, or 7 or 9, but let's use 1.
![\bf \begin{cases} x=-1\implies &x+1=0\\ x=3\implies &x-3=0 \end{cases}~\hspace{5em}\stackrel{\textit{even multiplicity}}{(x+1)^2}\qquad \stackrel{\textit{odd multiplicity}}{(x-3)^1}=\stackrel{y}{0} \\\\\\ (x^2+2x+1)(x-3)=y\implies x^3+2x^2+x-3x^2-6x-3=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill x^3-x^2-5x-3=y~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20x%3D-1%5Cimplies%20%26x%2B1%3D0%5C%5C%20x%3D3%5Cimplies%20%26x-3%3D0%20%5Cend%7Bcases%7D~%5Chspace%7B5em%7D%5Cstackrel%7B%5Ctextit%7Beven%20multiplicity%7D%7D%7B%28x%2B1%29%5E2%7D%5Cqquad%20%5Cstackrel%7B%5Ctextit%7Bodd%20multiplicity%7D%7D%7B%28x-3%29%5E1%7D%3D%5Cstackrel%7By%7D%7B0%7D%20%5C%5C%5C%5C%5C%5C%20%28x%5E2%2B2x%2B1%29%28x-3%29%3Dy%5Cimplies%20x%5E3%2B2x%5E2%2Bx-3x%5E2-6x-3%3Dy%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20x%5E3-x%5E2-5x-3%3Dy~%5Chfill)
Answer:
Maximum: 7
Minimum: 0
Step-by-step explanation:
A proper subset B of a set C, denoted
, is a subset that is strictly contained in C and so necessarily excludes at least one member of C.
This means that the number of elements in B must be at least 1 less than the number of elements in C. If the number of elements in C is 8, then the maximum number of elements in B can be 7.
The empty set is a proper subset of any nonempty set. Hence, the minimum number of elements in B can be 0.
Answer:
Step-by-step explanation:
7/12
1)7*2/12*2 = 14/24
2) 7*3 / 12*3 = 21/36
3) 7*4/12*4 = 28/48
X=-84. 3(x-6)+24=50+4(x+10)
distrubute. 3x-18+24=50+4x+40
move terms. 3x+6=90+4x
collect like terms 3x-4x=90-6
subtract -x=84
divide by -1. x=-84
Answer:
B. d = 5/3t
Step-by-step explanation:
The complete question is shown in the figure attached with.
We need to find the equation of direct variation using the graph. The general equation for a direction variation is:
y = kx
In this case, the variable along x axis is time in seconds i.e. "t" and the variable along y axis is distance in meters i.e. "d". So, the equation for this case would be:
d = kt
We need to find the value of "k" to complete this equation. For this we can use any point from the graph and substitute it in the above equation. From the graph we can see that the distance covered for time = 3 seconds is 5 meters. Substituting t =3 and d = 5 in above equation, we get:
5 = 3k
k = 5/3
Using the value of k in the above equation, we get:

Therefore, option B gives the correct answer