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Kay [80]
3 years ago
12

Find the inverse of the following function: f(x) = 5/ square root of x, for x > 0

Mathematics
2 answers:
UNO [17]3 years ago
7 0
The inverse is y = (5/y)^2

You can get this by switching the x and y values and then solving for your new y. 

x = 5/sqrt(y) ----> Multiply both sides by sqrt(y)
sqrt(y)*x = 5 ---> divide both sides by x
sqrt(y) = 5/x ---> square both sides
y = (5/x)^2
USPshnik [31]3 years ago
5 0

Answer:

f-1=25/x^2, for x>0

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}

Let say; By y(x)= y(e)  

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Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

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MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

y^{2} = {7+2Inx}  

y{x} = \sqrt{7+2Inx}

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Step-by-step explanation:

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