Answer:
a. P(x = 0 | λ = 1.2) = 0.301
b. P(x ≥ 8 | λ = 1.2) = 0.000
c. P(x > 5 | λ = 1.2) = 0.002
Step-by-step explanation:
If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

a. What is the probability of selecting a carton and finding no defective pens?
This happens for k=0, so the probability is:

b. What is the probability of finding eight or more defective pens in a carton?
This can be calculated as one minus the probablity of having 7 or less defective pens.



c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?
We can calculate this as we did the previous question, but for k=5.

I believe that the answer would be:
g(x) = 12x + 17
Answer:
Step-by-step explanation:
To find the inverse of function y=f(x), swap variables and then solve for the original variable.
![y=(x-5)^3+1\\ \\ x=(y-5)^3+1\\ \\ x-1=(y-5)^3\\ \\ \sqrt[3]{x-1}=y-5\\ \\ y=\sqrt[3]{x-1}+5\\ \\ f^{-1}(x)=\sqrt[3]{x-1}+5](https://tex.z-dn.net/?f=y%3D%28x-5%29%5E3%2B1%5C%5C%20%5C%5C%20x%3D%28y-5%29%5E3%2B1%5C%5C%20%5C%5C%20x-1%3D%28y-5%29%5E3%5C%5C%20%5C%5C%20%5Csqrt%5B3%5D%7Bx-1%7D%3Dy-5%5C%5C%20%5C%5C%20y%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5%5C%5C%20%5C%5C%20f%5E%7B-1%7D%28x%29%3D%5Csqrt%5B3%5D%7Bx-1%7D%2B5)