We have two points:
(-3,5) and (2,-3)
I
An equation in oint-slope form has this shape:
y-y₀=m(x-x₀)
m=slope
1) we compute the slope (m) between two points:
Given two points (x₁,y₁) and (x₂,y₂) the slope between these pointw will be.
m=(y₂-y₁)/(x₂-x₁)
In this case, our slope would be:
m=(-3-5)/(2+3)=-8/5
2) we choose one of these points and replace it in the equation, the result will be the same:
(-3,5)
<span>y-y₀=m(x-x₀)
</span>y-5=-8/5(x+3)
Answer: y-5=-8/5(x+3)
Answer:
y = 3x -1
Step-by-step explanation:
When the given points are dilated by a factor of 1/5 about the origin, each of the coordinate values is multiplied by 1/5. The points after dilation are ...
... (2/5, 1/5), (-1/5, -8/5)
The line through these points can be found starting with a 2-point form of the equation for the line.
... y -y1 = (y2 -y1)/(x2 -x1)·(x -x1)
Filling in the point values gives ...
... y -1/5 = (-8/5 -1/5)/(-1/5 -2/5)(x -2/5)
... y = (-9/5)/(-3/5)(x -2/5) +1/5 . . . . simplify parentheses, add 1/5
... y = 3x -1 . . . . . simplify
_____
The graph shows the original points and the line through them in red, and the dilated points and line in green.
Answer:
Top Right
Step-by-step explanation:
231/pi(3)^2 =8.17
Round down to 8
Answer:
d) 2i√15
Step-by-step explanation:
60/4 is 15 so you can take out the square of 2 and the -
6x^2 should be one of them if i am not mistaken!