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meriva
3 years ago
6

A hiker is at an elevation of 120 feet above sea level.

Mathematics
1 answer:
Artyom0805 [142]3 years ago
6 0

Answer:

Her car is 5 feet above sea level.

Step-by-step explanation:

The hiker is at 120 feet, she then goes 200 feet down which is 120-200. After going into the valley, she is at -80 feet. She then goes up 85 feet. -80+85=5. Her car is 5 feet above sea level.

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3 years ago
A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.
IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car (v_0) = 40 ft/sec

Deceleration of the car (\frac{dv}{dt}) = -10 ft/sec²

Final speed of the car (v_x) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, \frac{dv}{dt}=-10\ ft/sec^2

Negative sign means the velocity is decreasing with time.

Now, \frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt}) using chain rule of differentiation. Therefore,

\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft

Therefore, the car travels a distance of 80 feet before stopping.

4 0
3 years ago
In a certain month a family spent $750 on food .In third month the family spent $729 on food .What was percentage decrease in th
seraphim [82]

Answer: 2.8%

Step-by-step explanation:

Give, In a certain month a family spent $750 on food

In third month the family spent $729 on food .

i.e.  Expenditure on food in a certain month = $750

Expenditure on food in third month = $729

Decrease in monthly spending on food = (Expenditure in a certain month )- (Expenditure in third month )

= $750  -  $729

= $21

Now , the percentage decrease in the month spent on food will be :

\dfrac{\text{Decrease in monthly spending on food }}{\text{Expenditure on food in a certain month}}\times100\\\\=\dfrac{21}{750}\times100\\\\=2.8\%

Hence, the percentage decrease in the month spent on food  is 2.8%.

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4 years ago
Find the least common multiple of the set of polynomials 5x
Snezhnost [94]
The answer to this problem is 51
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3 years ago
Show all of your steps in solving the equation for full credit. (2 points) 6ln (x + 2.8) = 9.6
defon

1. You have to distribute the 61n into the parenthesis.

2. You get 61nx+170.8n=9.6

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