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vekshin1
3 years ago
6

How to solve f(x)=x2-8x+5

Mathematics
1 answer:
vfiekz [6]3 years ago
4 0

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:  

(

4

,

−

11

)

Focus:  

(

4

,

−

43

4

)

Axis of Symmetry:  

x

=

4

Directrix:  

y

=

−

45

4

x

y

2

−

7

3

−

10

4

−

11

5

−

10

6

−

7

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5. g(x) = 7x, find g(-7)
kompoz [17]

Answer:

just plug in

g(x)=7x

g(-7)=7*(-7)

7*(-7)=-49

Step-by-step explanation:

3 0
3 years ago
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
A package states that there are 60 calories in 12 crackers
kvv77 [185]

Answer: 5 calories = 1 cracker

Step-by-step explanation:

60:12 = 5:1

60 calories and 12 crackers = 5 calories and 1 cracker

7 0
3 years ago
Robert's Tea Shop has caffeinated tea and decaffeinated tea. The tea shop served 17 caffeinated teas and 51 decaffeinated teas.
TEA [102]
.333333.........% i cant write the little mark above it but it goes on continuosly.
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The signs of the product of 263 and 0 is
Mashcka [7]
The answer to the question is 0
6 0
3 years ago
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