Put the number of daughters as x and number of sons as y.
For the first half of the statement:
Number of sisters any daughter has = x-1 ( because you can't be your own sibling)
Number of brothers = y
y=x-1.
For the second half:
Number of sisters any son has = x
Number of brothers any son has = y-1
3(y-1)=x
Solve as system of equations.
3y-3=x
3(x-1)-3=x
3x-3-3=x
2x=6
x=3
y=x-1=3-1=2
3 daughters and 2 sons.
Hope this helps!
Your fortune is "You can't have everything...where would you put them all?"
So cancel each equation terms on both sides of the equation and move constant to the right side and change its sign. So your answer is A=-3
Your welcome
Answer:
b
Step-by-step explanation:
the second one it should be hope's it helps
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Answer:
5x+4
Step-by-step explanation:
6x+8-x-4
5x+4
