For this case we have the following function:
f (t) = -16t2 + 32t + 384
By definition we have to:
The average rate of change:
AVR = (f (t2) - f (t1)) / (t2 - t1)
Where,
For t1 = 4
f (4) = -16 * (4) ^ 2 + 32 * (4) + 384
f (4) = 256
For t2 = 6
f (6) = -16 * (6) ^ 2 + 32 * (6) + 384
f (6) = 0
Substituting values we have:
AVR = (0 - 256) / (6 - 4)
AVR = -128
Answer:
The average rate of change of f (t) from t = 4 seconds to t = 6 seconds is -128 feet per second.
2/3x=7/84
16=1
9=4
The solución is by dividing
The answer is 12 becasue you’re trying to find the leg
<h3>
Answer: Choice A) 1/3</h3>
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Work Shown:
x = preimage length = 12
y = image length = 4
z = scale factor
z = y/x
z = 4/12
z = (1*4)/(3*4)
z = 1/3
The scale factor is 1/3.
This means the image is 1/3 of the length of the preimage.
Answer:
10^100 is larger than 100^10.
Step-by-step explanation:
10^100 compared to 100^10, we have 10^100 greater. 100^50 would equal to 10^100, as 10^2=100. 10^100 would be much more than 100^10.
Hope the explanation helps!
