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aliya0001 [1]
3 years ago
6

What is the scale factor for this dilation? Show your work!

Mathematics
1 answer:
sattari [20]3 years ago
3 0

Answer:

The scale factor is 2/3.  

Step-by-step explanation:

On point M, the point is (-3, 3).  The x value, -3 times 2/3 = -2, and the y-value, 3 times 2/3 = 2.  Same goes for the rest of the points.  

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Step-by-step explanation:

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3 years ago
If p(x) = x2 – 1 and 9(x) = 5(x-1), which expression is equivalent to (p - 9)(x)?
Westkost [7]

For this case we have the following functions:

p (x) = x ^ 2-1\\9 (x) = 5 (x-1)

We must find (p-9) (x). By definition of composition of functions we have:

(p-9) (x) = p (x) -9 (x)

So:

(p-9) (x) = x ^ 2-1- [5 (x-1)] = (x ^ 2-1) -5 (x-1)

Thus, the correct option is option C.

Answer:

(x ^ 2-1) -5 (x-1)

Option C

4 0
3 years ago
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taurus [48]

Answer:

No

Step-by-step explanation:

The first 3 boxes are proportional since they have a ratio of 1:3, but 6:21 is not proportional to the others.

6 0
3 years ago
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What are the measures of jk and _KIJ?
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I really don’t know Bc I’m trying to get mine
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Discrete Mathematics I
faust18 [17]

ANSWER



The general solution is 86+280n, where n is an  integer



<u>EXPLANATION</u>



In order  to solve the linear congruence;



33x \equiv 38(mod\:280)



We need to determine the inverse of 33 (which is a Bézout coefficient for 33).



To do that we must first use  the Euclidean Algorithm to verify the existence of the inverse by showing that;



gcd(33,\:280)=1



Now, here we go;



280=8\times33+16



33=2\times 16+1



16=2\times 8+0



The greatest common divisor is the last remainder before the remainder of zero.



Hence, the gcd(33,\:280)=1.



We now express this gcd of 1 as a linear combination of  33 and 280.



We can achieve this by making all the non zero remainders the subject and making a backward substitution.



1=33-2\times 16--(1)



16=280-33\times8--(2)



Equation (2) in equation (1) gives,



1=33-2\times (280-8\times33)



1=33-2\times 280+16\times33



1=17\times33-2\times 280



The above linear combination tells us that  17 is the inverse of 33.



Now we multiply both sides of our congruence relation by 17.



17\times 33x \equiv 17\times 38(mod\:280)



This implies that;



x \equiv 646(mod\:280)



x \equiv 86.



Since this is modulo, the solution is not unique because any integral addition or subtraction of the modulo (280 in this case) produces an equivalent solution.



Therefore the general solution is,



86+280n, where n is an  integer

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4 years ago
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