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m_a_m_a [10]
2 years ago
13

im not that good at functions so is this right? if not could you explain how to do the problem? 25 points

Mathematics
2 answers:
Charra [1.4K]2 years ago
8 0

I will find one by one

\\ \sf\longmapsto f(x)=2x-1

\\ \sf\longmapsto f(1)=2(1)-1=2-1=1

\\ \sf\longmapsto f(0)=2(0)-1=-1

\\ \sf\longmapsto f(-1)=2(-1)-1=-1-1=-3

\\ \sf\longmapsto f(2)=2(2)-1=4-1=3

Studentka2010 [4]2 years ago
6 0

Answer:

f(1) = 2*1 - 1 = 1

f(0) = 2*0 - 1 = -1

f(-1) = 2*-1 - 1 = -3

f(2) = 2*2 - 1 = 3

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Solve quadratic equation (x-3)^2+5=14
laiz [17]

Answer:

the Answer is 14=5+2^(3-x)

Step-by-step explanation:

6 0
3 years ago
Point K is graphed on a number line at 3. Point L is 11 units away from point K on the number line.
notsponge [240]
3+/-11
add 11 to 3
11+3=14
minus 11 from 3
3-11=-8

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6 0
3 years ago
A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the
Kay [80]

Answer:  The required number of quarters in the collection is 11.

Step-by-step explanation:  Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05,   1 dime = $ 0.10   and    1 quarter = $0.25.

Then, according to the given information, we have

x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)

and

y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Comparing the values of y from equations (iv) and (v), we get

47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.

Thus, the required number of quarters in the collection is 11.

7 0
2 years ago
Can someone help me plz??
Brrunno [24]

Answer: 23

Step-by-step explanation:

2x + 14 = 60

2x = 46

x = 23

6 0
2 years ago
Solve for x. 26x2–9x=0
Lilit [14]

Answer:

x=0;x=\frac{9}{26}

Step-by-step explanation:

assuming you meant 26x^2-9x=0:

26x^{2} -9x=0\\x(26x-9)=0\\x=0;x=\frac{9}{26}

3 0
2 years ago
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