Question

URGENT! Can someone please help me?​

Answer 1

Answer:

An equation of the circle with centre (5,7) and radius 2 is $\mathbf{(x-5)^2+(x-7)^2=4}$

Option A is correct.

Step-by-step explanation:

A circle in the xy-plane has centre (5,7) and radius 2. Which of the following is an equation of the circle.

The equation of circle is of form: $(x-h)^2+(x-k)^2=r^2$ where (h,k) is centre and r is radius.

We have centre (5,7) so, we have h = 5 and k = 7

We have radius = 2 so, r = 2

Putting values in the equation and finding the required equation:

$(x-h)^2+(x-k)^2=r^2\\(x-5)^2+(x-7)^2=(2)^2\\(x-5)^2+(x-7)^2=4$

So,  an equation of the circle with centre (5,7) and radius 2 is $\mathbf{(x-5)^2+(x-7)^2=4}$

Option A is correct.