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g100num [7]
3 years ago
12

URGENT! Can someone please help me?​

Mathematics
1 answer:
katovenus [111]3 years ago
3 0

Answer:

An equation of the circle with centre (5,7) and radius 2 is \mathbf{(x-5)^2+(x-7)^2=4}

Option A is correct.

Step-by-step explanation:

A circle in the xy-plane has centre (5,7) and radius 2. Which of the following is an equation of the circle.

The equation of circle is of form: (x-h)^2+(x-k)^2=r^2 where (h,k) is centre and r is radius.

We have centre (5,7) so, we have h = 5 and k = 7

We have radius = 2 so, r = 2

Putting values in the equation and finding the required equation:

(x-h)^2+(x-k)^2=r^2\\(x-5)^2+(x-7)^2=(2)^2\\(x-5)^2+(x-7)^2=4

So,  an equation of the circle with centre (5,7) and radius 2 is \mathbf{(x-5)^2+(x-7)^2=4}

Option A is correct.

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We want to factor the following expression: 25x^2−36y^8 We can factor the expression as (U+V)(U-V) where U and V are either cons
Aneli [31]

Answer:

U=5\,x

V=6\,y^4

Step-by-step explanation:

Recall that an expression that can be factored as (U+V)(U-V) using distributive property for multiplication of binomials, should render:  U^2-V^2 (the factorization given above is that of a difference of squares. Then, the idea is to write the original expression :

25\,x^2-36\,y^8

as a difference of perfect squares. Let's examine each term and its numerical and variable form to find if they can be written as perfect squares:

a) the term   25\,x^2=5^2\,x^2=(5x)^2 therefore, if we assign the letter U to 5\,x, the first term becomes:

25\,x^2=(5\,x)^2=U^2

b) the term   -36\,y^8=-6^2\,(y^4)^2=-(6\,y^4)^2  therefore, if we assign the letter V to  6\,y^4 , this second term becomes:

-36\,y^8=-(6\,y^4)^2=-V^2

With the above identification, our expression can now be factored as a difference of squares:

25\,x^2-36\,y^8=(5\,x)^2-(6\,y^4)^2=U^2-V^2=(U+V)(U-V)

5 0
3 years ago
Which weighs more 5 ounces or 150 grams
Karo-lina-s [1.5K]
150 grams weigh more than 5 ounces
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3 years ago
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What is the decimal equivalent to 66%?
igomit [66]

Answer:

0.66

Step-by-step explanation:

Note: ALWAYS divide the percentage by 100.

7 0
3 years ago
Please find the general limit of the following function:
valentinak56 [21]

Answer:

The general limit exists at <em>x</em> = 9 and is equal to 300.

Step-by-step explanation:

We want to find the general limit of the function:

\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))

By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.

So, let's find each one-sided limit: the left-hand side and the right-hand side.

The left-hand limit is given by:

<h3>\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))</h3>

Since the given function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

300

Therefore:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300

The right-hand limit is given by:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))

Again, since the function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

=300

Therefore:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Thus, we can see that:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.

8 0
3 years ago
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vlada-n [284]

Answer:

I belive it would be x<84

Step-by-step explanation:

please let me know if i am wrong

3 0
3 years ago
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