Help i would like an explanation if possible and Im not smart

riadik2000 [5.3K]

Answers:

Domain is $0 \le d \le 100$

Range is $0 \le F(d) \le 150$

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Explanation:

The most money made from selling drinks is $150. Divide this over the cost per drink to get 150/(1.50) = 100; indicating that at most 100 drinks are sold per day. This is the largest that d can get because d represents the number of drinks sold.

The smallest d can get is d = 0 to mean that no drinks are sold.

In short: d is between 0 and 100, including both endpoints. We write $0 \le d \le 100$ to indicate this. This is the domain because the domain represents all the possible inputs allowed.

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The range is the set of allowed outputs.

If we plugged in d = 0, then you would find F(d) = 0 as well. If you don't sell any drinks, then you earn $0. This is the smallest item in the range.

On the other side of things, the largest item in the range is 150 because this value was given to us. It's the upper limit or ceiling value of how much money is made from drinks. You can also find this by plugging d = 100, the largest domain value, into the function to get F(d) = 150.

Therefore the range is $0 \le F(d) \le 150$ to indicate that F(d) is between 0 and 150 inclusive of both endpoints.

8 0

3 years ago

A.

professor190 [17]

Answer:

I think it's A im not entirely sure tho .

Step-by-step explanation:

8 0

4 years ago

The function y = 58. 7(1. 03)^t gives a country’s population, y (in millions), where t is the number of years since January 1994

GREYUIT [131]

Answer:

Approximate population ≈ 74.36 million.

Step-by-step explanation:

The given problem involves modeling of an exponential growth or decay function of a population.

<h2>Definition:</h2>

Exponential growth ( relative growth ) occurs when a population grows or increases exponentially by the same factor, over the same amount of time.
Exponential decay occurs when a population decreases continuously by a constant factor, over the same amount of time.

We can model the exponential growth of a population using the following Exponential Growth Model:

⇒ $\displaystyle\mathsf{P(t)\:=\:P_0 (1\:+\:r)^t }$

Where:

P( t ) = population after "t" years
P₀ = initial population
r = relative growth rate; positive "r" value means that the population is increasing; negative "r" value implies that the population is decreasing.
t = time (typically in years)

<h2>Solution:</h2>

Based from the given equation, $\displaystyle\mathsf{y\:=\:58.7(1.03)^t }$ , we can infer that:

⇒ $\displaystyle\mathsf{P(t)\:=\:P_0 (1\:+\:r)^t }$ or $\displaystyle\mathsf{y\:=\:P_0 (1\:+\:r)^t }$

Where:

P( t ) or y = population after "t" years
P₀ = initial population = 58.7
r = relative growth rate = 0.03 or 3% = the population is increasing (exponential growth).
t = time (typically in years) = 8 years (difference between January 2002 and January 1994).