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juin [17]
2 years ago
9

4.Which is the best buy in the following cases.a) 4 pens for 56 or 6 pens for rs 90​

Mathematics
2 answers:
larisa [96]2 years ago
7 0

<u>✨</u><u>Answer:</u><u>✨</u>

4 pens for $56

<u>✨Step-by-step explanation:✨</u>

$56 ÷ 4 pens = $14 dollars per pen

$90 ÷ 6 pens = $15 dollars per pen

4 pens for $56 is the better buy because each pen will cost $14.

Hopefully this helps! Sorry if wrong. You are loved, and you are beautiful/handsome!

-Bee

alukav5142 [94]2 years ago
4 0

Answer:4 pens for 56

Step-by-step explanation:

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Please help me with this! Picture is provided and only answer is you know it!
Sophie [7]

Answer:

Option A

Step-by-step explanation:

Number of components assembled by the new employee per day,

N(t) = \frac{50t}{t+4}

Number of components assembled by the experienced employee per day,

E(t) = \frac{70t}{t+3}

Difference in number of components assembled per day by experienced ane new employee

D(t)= E(t) - N(t)

D(t) = \frac{70t}{t+3}-\frac{50t}{t+4}

      = \frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}

      = \frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}

      = \frac{20t^2+130t}{(t+3)(t+4)}

      = \frac{10t(2t+13)}{(t+4)(t+3)}

Therefore, Option A will be the answer.

3 0
3 years ago
Kendall recently received a job offer which required him to move his house full of furniture across the country from Columbia, S
Valentin [98]
X,y
1092, 109
671, 67
985, 99
The rate is 10.02 and I found that by dividing x with y
6 0
3 years ago
Read 2 more answers
Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
sweet [91]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

The concepts of mutually exclusive events and independent events are not the same.

(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0
3 years ago
The average (arithmetic mean) of five different positive integers is 30. What is the greatest possible value of one of these int
geniusboy [140]

Answer:

The Greatest possible value of one of the integer is 140.

Step-by-step explanation:

Given:  The average (arithmetic mean) of five different positive integers is 30.

To find:  What is the greatest possible value of one of these integers?

Explanation: we are given that the arithmetic mean of five  positive integer

                   is 30.

Let the five positive integers are A,B,C,D,E

The arithmetic mean :

                   \frac{A+B+C+D+E}{5} =30.

On multiplying both side by 5.

                       A+B+C+D+E =150.

The least values of A ,B,C and D can be 1 ,2,3,4.

  Then :  1 +2+3+4+E =150

On simplification  10+E =150

On subtraction both side by 10 we get

                      E = 140 .

Therefore, the Greatest possible value of one of the integer is 140.


6 0
3 years ago
Cable has 24 pennies he has hafe as many nickels as pennies he has 5 more dimes than nickels he has 6 fewer quarters than dimes
Andreyy89
Pennies (P) = 24
Nickels = 1/2P
Dimes = 1/2P + 5
Quarters = (1/2P + 5) -6

Therefore...

Nickels = 1/2P = 1/2(24)= 12
Dimes = 12 + 5 = 17
Quarters = 17 - 6 = 11
6 0
3 years ago
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