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Semenov [28]
3 years ago
12

Let f(x) = 4 – x^2, g(x) = 2 – x. Find (f + g)(x) and its domain.

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Step-by-step explanation:

f(x)=4-x^2,\ g(x)=2-x\\\\(f+g)(x)=f(x)+g(x)\\\\\text{therefore}\\\\(f+g)(x)=(4-x^2)+(2-x)=-x^2-x+(4+2)=-x^2-x+6\\\\\text{It's the quadratic function. The domain is the set of all real numbers}\ x\in\mathbb{R}

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A movie theater charges $10 for adult tickets and $7 for child tickets. On a particular day, they made $1446 in ticket sales. Th
luda_lava [24]
X = adults
Y = child

X+y=168
X=168-y

$10x + $7y = $1446

10(168-y) + 7y = 1446
1680 - 10y + 7y = 1446
-3 y = -234
Y = 78

X = 168-78
X = 90

$10*90 + $7*78 =
$900 + $546 = $1446
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maria [59]

Answer: -3

Step-by-step explanation:

6 0
3 years ago
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The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
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The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4  or 1.85
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Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
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3 years ago
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the tank holds 4 gallons


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In this assignment, you will explore how the volume is changed when you adjust the height or radius of a cylinder. You will drag
lesantik [10]

The volume of a cylinder changes when you adjust the height or radius as the volume either increases or reduces.

<h3>How to illustrate the volume?</h3>

Let's assume that the height and radius are 14cm and 7cm. The volume will be:

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= 3.14 × 7² × 14

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When the radius and height are reduced to 5cm and 9cm, the volume will be:

= πr²h

= 3.14 × 5² × 9

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This illustrates that the volume reduces when the height and radius reduces.

Learn more about volume on:

brainly.com/question/1972490

#SPJ1

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2 years ago
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