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vazorg [7]
2 years ago
7

How to realize dynamic balance of planar closed-chain leg mechanism?​

Computers and Technology
2 answers:
Alexxandr [17]2 years ago
5 0

The common belief is that Closed Chain exercises are the preferred rehabilitation for anterior cruciate ligament (ACL) injury because of increased strain.

djyliett [7]2 years ago
4 0

The dynamic balance of planar closed-chain leg mechanism can be realized through high precisions and short cycle times.

  • It should be noted that the closed-chain leg mechanism is vital as it's used as spokes for wheels, robots, etc.

  • Dynamic balance simply means the ability of an object to be able to balance while it's in motion or when it switches between positions.

  • The closed-chain leg mechanism is important for the structural transformation that can be found between the legged mode and the wheeled model.

In conclusion, high precision is important to realize dynamic balance of planar closed-chain leg mechanism.

Learn more about dynamic balance on:

brainly.com/question/24812026

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[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
You can invoke or call a method from another program or method. When methods must share data, you can pass the data into and ret
san4es73 [151]

Answer:

1. You can invoke or call a method from another program or method: TRUE

2. When methods must share data, you can pass the data into and return the data out of methods: TRUE

3. A method could be called using any numeric value as an argument, whether it is a variable, a named constant, or a literal constant: TRUE

Explanation:

4 0
3 years ago
Bunch of points!!!!!!! help pls
alex41 [277]
Most likely B. Photographs.

Hope this helps!

Have a good day!
4 0
3 years ago
Read 2 more answers
Select the correct line of missing code to create an output of "hello."
s2008m [1.1K]

Answer:

B

Explanation:

This feels like an error on the question issuer's part.

3 0
2 years ago
Quality answers will be appriciated! :)​
Naddika [18.5K]
<h2>1.</h2>

  1. F
  2. T
  3. T
  4. T
  5. F
  6. F
  7. T

________

<h2>2.</h2>

  1. A
  2. B
  3. D5*E5
  4. A

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2 years ago
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