Answer:
Step-by-step explanation:
Number 5 is third option
and number 6 is second option
Answer:
false
Step-by-step explanation:
standard form cannot contain fractions or decimals
Answer: Terminating
Step-by-step explanation: Although the 0 is repeating, a 0 doesn't really mean anything as it is after the numbers. That number is just 0.012. The zeros are unnecessarily there.
We can rewrite the expression under the radical as

then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that

since both
and
return the same number
, and
captures both possibilities. From here, we have

The absolute values disappear on all but the
term because all of
,
and
are positive, while
could potentially be negative. So we end up with
