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1 year ago

6

Mathematics

1 answer:

Mumz [18]1 year ago

5 0

Answer:

112.81 miles

Step-by-step explanation:

304.6 divided by 2.7

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Help please. 10 points yall.

vitfil [10]

A.) 2a+6b

Explanation:
multiply each term in parentheses by 2
2a+2x+3b
calculate the product
2a+6b

3 0

2 years ago

Please help me with NUMBER 7 !! Thank you so much! 20 points!! :))

mart [117]

Answer:

x<-3 or x>-1

Step by step explanation:

Start with -5x>15. To get x by itself, we have to divide each side by -5. When we do that we get x<-3. (Don't forget to flip the sign when dealing with negative · and ÷.) Now answer the second equation. x-5>-6 To get x by itself, add 5 to both sides to get x>-1. Now we have x<3 or x>-1.

8 0

2 years ago

Y = -3x-2 Slope intercept form

lana66690 [7]

Answer:The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept. The y-intercept of this line is the value of y at the point where the line crosses the y axis.

Step-by-step explanation:

4 0

2 years ago

HELP ASAP

Oliga [24]

Answer:

27.5cm^2

Step-by-step explanation:

you can cut the triangle to make two right triangles

so 11 is the height and the width is 2.5 since your cutting the triangle in half

so 11x2.5=27.5 since its a right triangle you have to divide by two 27.5/2=13.75

that's the answer for one of the triangles now multiply it by two since you need the two right triangle to make the other triangle so the answer is 27.5

5 0

2 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

5 months ago