All categories

3 years ago

Can someone help I don’t understand

Mathematics

1 answer:

Allushta [10]3 years ago

6 0

Answer:

A: 20 ft

Step-by-step explanation:

Hopefully this helps!

You might be interested in

I need help. See picture:<br> "Number of solutions to equations challenge"

Zanzabum

Answer:

Step-by-step explanation:

Put the values of P and Q to the equation Px - 45 = Qx + 75:

15x - 45 = 15x + 75 <em>subtract 15x from both sides</em>

-45 = 75 FALSE

In other cases, we get some value x.

Example:

A. P = -45 and Q = -75

-45x - 45 = -75x + 75 <em>add 45 to both sides</em>

-45x = -75x + 120 <em>add 75x to both sides</em>

25x = 120 <em>divide both sides by 25</em>

x = 4.8

3 0

3 years ago

Find the inverse of the given function

Svetradugi [14.3K]

Answer:

f^-1(x) = 4x^2 -3 . . . . x ≤ 0

Step-by-step explanation:

Interchange x and y, then solve for y.

x = -1/2√(y+3)

-2x = √(y +3)

4x^2 = y +3

4x^2 -3 = y

Note that the range of the function f(x) is f(x) ≤ 0, so this will be the domain of the inverse function. Then the inverse function is ...

f^-1(x) = 4x^2 -3 . . . . for x ≤ 0

___

The attached graph shows this inverse function is a reflection of the function across the line y=x, as it should be.

3 0

3 years ago

How do you find the measure of angle 3

Margaret [11]

Answer:

My guess is 68 degrees too. It's connected to 3. Could be wrong though.

8 0

3 years ago

Read 2 more answers

What is the volume for this picture

Gekata [30.6K]

Answer:

add it all and yu wil get all the answer and multiple it

5 0

3 years ago

Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).

Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

$\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).$

Then

$\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.$

2. Find

$\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).$

Then

$\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.$

3. Find

$\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).$

Then

$\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.$

$\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.$

3 0

3 years ago