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2 years ago

Can someone help I don’t understand

Mathematics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

A: 20 ft

Step-by-step explanation:

Hopefully this helps!

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The scatterplot shows the distance (in feet) that a person was from a motion sensor during an experiment in math class. Use the

iragen [17]

Answer:

B.) 27ft

Step-by-step explanation:

The labeled points given: (5,18) and (1.5, 7.5)

Slope = (18 - 7.5)/(5-1.5) = 10.5 / 3.5 = 3

A linear model:

y - 18 = 3(x - 5)

y - 18 = 3x - 15

y = 3x + 3

If x = 8 seconds then the distance in feet (y) would be: (plug in x = 8 into the equation y = 3x + 3)

y = 3(8) + 3

y = 24 + 3

y = 27 ft

Answer:

B.) 27ft

8 0

3 years ago

Read 2 more answers

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

3.5 cm = to what ml

zaharov [31]

3.5 cubic centimeters is also equivalent to 3.5 ml

6 0

3 years ago

Simplify sec(t)cot(t) to a single trig function or constant with no fractions

lana66690 [7]

Answer:

make it make sense then could answer

4 0

2 years ago

Slove these 2questions

mart [117]

To find the scale factor divide the bigger measurement by the smaller one.

You did number 17. 42 / 3 = 14 so your scale factor is 14, option D.

For number 18, 48 / 6 = 8 so option A.

6 0

2 years ago