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Nadya [2.5K]
2 years ago
13

Select the correct answer.

Mathematics
2 answers:
vesna_86 [32]2 years ago
7 0

The highlighted part of the triangle is an angle. It is on the inside of the triangle and formed by two sides coming together.

Hope this helps! :)

o-na [289]2 years ago
3 0

Answer:

Angle

Step-by-step explanation:

Vertices (plural for vertex) are basically the points of the triangle.

Angles are the amount of space between two line segments (typically measured in degrees)

Sides are line segments of a shape.

Therefore, B is right.

You might be interested in
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun
AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

               Nonsmokers      Light Smoker     Heavy smoker      Total

Men                        303                     35                           37        375

Women                   413                     31                            45        489

Total                        716                     66                           82        864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

nCx=\frac{n!}{x!(n-x)!}

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

82C2=\frac{82!}{2!(82-2)!}=3321

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

864C2=\frac{864!}{2!(864-2)!}=372816

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908

4 0
3 years ago
Please answers all these questions for me need help too pass plz help☺
vodka [1.7K]

Please take 1 minute, and really read the example solution
under problem #12.  All of the other eight problems on the
sheet are solved in exactly the same way:

Multiply each side of the equation by the denominator of
the fraction ... the number under the variable (the letter).

This easy step will get you the answer to each of the
eight problems.

I can't help noticing that the title of the sheet is 'extra PRACTICE' .
If someone handed you the answers, then you would not get the
practice.  That would be just like stealing from you, and would be
just plain mean.

8 0
3 years ago
Please help nwidnlqknwsam
cestrela7 [59]

Answer:

Part A: Missing Numbers are 64 and 7 going downwards

Part B: Make a TABLE representing how much money they made for 5, 6, 8 hours which they made $64

Part C: ??

Step-by-step explanation:

7 0
3 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
Write the expression in exponential form.<br> log 3^9= 2
denis23 [38]

Answer: 3^2

Step-by-step explanation:

remember logb a=n <---> a=b^n

so therefor the answer is log3 9=2 ---> 9 = 3^2

5 0
3 years ago
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