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balu736 [363]
2 years ago
13

5

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
5 0
2 pounds per person
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When a jug is half- filled with marbles, it weighs 2.6 kg. The jug weighs 4 kg when it is full. Find the weight of the empty jug
baherus [9]

the difference between a full jug and a jug that is half full will give us the weight of the marbles only in a half full jug:
4 - 2.6 = 1.4 kg

In a half full jug that weighs 2.6 kg, the weight of the marbles is 1.4 kg 
the weight of the jug = 2.6 - 1.4 = 1.2 kg

5 0
3 years ago
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Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. If this player shoots twi
Kipish [7]

Answer:

<em>The probability of scoring two goals in both times is</em><em> 0.137 or 13.7%</em>

Step-by-step explanation:

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

So P(A)=0.63

Hence, the probability of getting success in his shoots will be,

P(A^c)=1-P(A)=1-0.63=0.37

The probability of scoring two goals in both times is,

=P(A^c)\cdot P(A^c)

=0.37\times 0.37

=0.137

=13.7\%

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3 years ago
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72 = 8 x 9
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3 years ago
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In what form is the following linear equation written v=9x+2
Oksi-84 [34.3K]
Taking v to be y, it's written in the standard form for a linear equation, y=mx+c
6 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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