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weeeeeb [17]
2 years ago
11

Pomelo and Calamansi Trees are type of plants that suitable in this method.A. Cleft-Grafting B. Marcotting C. Layering D. T-Budd

ing
Computers and Technology
1 answer:
Olegator [25]2 years ago
8 0
Pomelo and Calamansi Trees are type of plants that suitable in this method.A. Cleft-Grafting
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Maia notices that her paragraphs are too close to one another. She wants to increase the space. Which arrangement of steps does
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7 0
3 years ago
Read 2 more answers
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
3 years ago
Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example
Evgesh-ka [11]

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

   int sum, i; //declaring variable

   sum=m; //holding value of m variable

   for(i=++m;i<=n;i++) //loop for calculate number between given range  

   {

   sum=sum+i; //adding value

   }

   printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

   int m,n; //defining integer variable

   printf("Enter m value: "); //message

   scanf("%d",&m); //input value by user in variable

   printf("Enter n value: "); //message

   scanf("%d",&n);//input value by user in variable

   inc(m,n); //calling method

   return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

  • The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
  • In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.
7 0
3 years ago
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