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3 years ago

Andre is making paper cranes to decorate for a party. He plans to make one large paper

Mathematics

1 answer:

tatiyna3 years ago

8 0

Answer:

10 + 3x </= 30

x </= 6.666

He can make at most 6 cranes before his time runs out. He would be 2/3 through the next small one when time runs out.

Step-by-step explanation:

10 + 3x </= 30

10 is the minutes for the centerpiece

3 is the minutes to make each small crane

x is the number of small cranes he can make

he has less than or equal to 30 minutes to complete them.

10 + 3x </= 30

subtract 10 from both sides

3x </= 20

x </= 6.666

He can make at most 6 cranes before his time runs out. He would be 2/3 through the next small one when time runs out.

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Answer:

No solutions

Step-by-step explanation:

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|-2x-10| + 4-4 = 2-4

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The absolute value is negative so there are no solutions.

Absolute values are always positive, so they cannot be negative.

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3 years ago

In which quadrant did the square end up after being translated 5 units to the left?

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Answer:

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Step-by-step explanation:

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2 years ago

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What’s the area of this shape

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The shape at the top is a trapezoid with width 2 cm and lengths 4 and 8 cm.

Its area is

4+8

-------- 2 cm = 12 cm^2

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3 years ago

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An arrow is shot vertically upward from a platform 20 ft high at a rate of 179ft / s * e When will the arrow hit the ground ? Us

MissTica

The height attained by the arrow is modelled as,

$h(t)=-16t^2-v_{\circ}t+h_{\circ}$

Given that the initial height is 20 ft and the initial velocity is 179 ft per second,

$\begin{gathered} v_{\circ}=179 \\ h_{\circ}=20 \end{gathered}$

Substitute the values,

$\begin{gathered} h(t)=-16t^2-(179)t+(20) \\ h(t)=-16t^2-179t+20 \end{gathered}$

When the arrow hits the ground its height will become zero,

$\begin{gathered} h(t)=0 \\ -16t^2-179t+20=0 \end{gathered}$

Applying the quadratic formula,

$\begin{gathered} t=\frac{-(-179)\pm\sqrt[]{(-179)^2-4(-16)(20)}}{2(-16)} \\ t=\frac{179\pm\sqrt[]{33321}}{-32} \\ t=\frac{179\pm182.54}{-32} \\ t=\frac{179+182.54}{-32},t=\frac{179-182.54}{-32} \\ t=-11.298,t=0.1106 \end{gathered}$

Since time cannot be negative, we have to neglect the negative value.

Thus, it can be concluded that the arrow will hit the ground after 0.1106 seconds approximately.

7 0

7 months ago

Pls help me. I'm lost

Ket [755]

Answer:

f(-2) = 13

g(4) = -9

Explanation:

Whenever a question is asking you to find something like, in this example, f(-2) or g(4), you have to substitute whatever number is in the parentheses for every x in the function with that letter.

Let's try to find f(-2). We have to substitute -2 for every x in the function f and simplify:

$f(-2) = -2 (-2)^{3} -3\\f(-2) = -2(-8)-3\\f(-2) = 16 - 3 \\f(-2) = 13$

Therefore, $f(-2) = 13$ .

Next, let's try to find g(4). We have to substitute 4 for every x in the function g and simplify:

$g (4) = -2(4) - 1\\g(4) = -8-1\\g(4) = -9$

Therefore, $g (4) = -9.$

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2 years ago