Answer:
Total money they had at first $252.
Step-by-step explanation:
Let,
x be the amount Silas had originally
y be the amount Raja had originally
According to given statement;
x = 3y Eqn 1
x - 84 = y + 42 Eqn 2
Putting x=3y in Eqn 2
3y - 84 = y + 42
3y - y = 42 + 84
2y = 126
Dividing both sides by 2
Putting y = 63 in Eqn 1
x = 3(63)
x = 189
Total money they originally had = 189 + 63 = $252
Hence,
Total money they had at first $252.
Answer:
2
Step-by-step explanation:
7x + 3 = 8x + 1
2 = x
these are geometry problems.
Answer:
33/20
Step-by-step explanation:
1/12 - 1/15 = 5/60 - 4/60 = 1/60
d = 1/60
a_n = a_1 + d(n - 1)
a_11 = 1/15 + (1/60)(11 - 1)
a_11 = 1/15 + 1/6
a_11 = 4/60 + 10/60
a_11 = 14/60
a_11 = 7/30
a_12 = 14/60 + 1/60
a_12 = 15/60
a_12 = 1/4
s_n = n(a_1 + a_n)/2
s_11 = 11(1/15 + 7/30)/2
s_11 = 11(2/30 + 7/30)/2
s_11 = 11(9/30)/2
s_11 = 99/60
s_11 = 33/20
Answer:
y = 1 1/9
BRO MAKE ME THE BRAINLIEST PLS
