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2 years ago

I will give brainliest if applicable

Mathematics

1 answer:

insens350 [35]2 years ago

8 0

Answer:

The average is exactly 26,375 gallons of gas per hour.

How I found this is buy subtracting each numbers like 422,000 - 369,250 = 52,750. 369,250 - 316,500 = 52, 750 and so on. They all ended up being 52,750, but then I realized that they are all 2 hours apart and the question asks of gallons of gas per 1 hour so then I divided 52,750 in half and got my final answer, 26,375.

Step-by-step explanation:

This is how much gas the jet uses per 1 hour

my question doesn't ask me to create a linear model but it asks for gasoline per hour, and it's just like this question with the same graph so if you have the same as me this is the answer.

You might be interested in

WILL MEDAL help me if please

nordsb [41]

1. Use the FOIL method (x+9)(x+9)
First, outer, inner, last
$x^{2} +9x+9x+81$
Add your like terms
$x^{2} +18x+81$

2. When you add or subtract polynomials you add or subtract the like terms and then put them in order from largest to smallest exponents.

3. $-5x(5 x^{3} +10 x^{2} -6x+3)$

4. Since it is the perimeter, we add the 3 together.
$(2 x^{2} +4x-3)+(-3 x^{2} -3)+(5x+19)$
Add the like terms together:
$2 x^{2} +(-3 x^{2} )=- x^{2} \\ 4x+5x=9x \\ -8+(-3)+19=8$
Put them in order of exponents
$- x^{2} +9x+8$

Hope this helps

8 0

3 years ago

. A retailer sold 10 packs of pens in 3 days. There were 48 pens in each pack. He sold twice as many pens on Sunday than on Mond

Marizza181 [45]

Answer:

The number of pens sold on Monday is 107 pens

Step-by-step explanation:

total pack of pen sold by the retailer in 3 days = 10 packs

total number of pens in the 10 packs = 48 x 10 = 480 pens

let the number of pens sold on Monday = x

let the number of pens sold on Sunday = y

let the number of pens sold on Tuesday = z

He sold twice as many pens on Sunday than on Monday

y = 2x ------equation (1)

He sold 55 pens fewer on Tuesday than on Sunday

y = z + 55 ------equation (2)

total number of pens sold in the three days

y + z + x = 480 ------equation (3)

from equation (1) make x the subject of the formula

x = y/2

from equation (2) make z the subject of the formula

z = y - 55

substitute the value of x, and z into equation (3)

y + y/2 + y - 55 = 480

2y + y/2 = 480 + 55

5y/2 = 535

5y = 535 x 2

5y = 1070

y = 1070 / 5

y = 214

The number of pens sold on Monday is:

x = y / 2

x = 214 / 2

x = 107 pens

Thus, the number of pens sold on Monday is 107 pens

5 0

3 years ago

(02.03)

RoseWind [281]

Answer:

It's the one under the one you have selected.

Step-by-step explanation:

7:2

14:4

28:8

56:16

Divide the first number by 7 then multiply it by 2.

Example: 56/7=8, 8*2=16 so it's correct.

4 0

3 years ago

Read 2 more answers

Write an expression for the product of 11 and w

Nadya [2.5K]

Answer:

11 * w

Step-by-step explanation:

"product" in math means "multiply". "The product of 11 and w" is "the multiplication of 11 and w".

Write the expression:

The Multiplication: *

11 and w: 11 * w

11 * w is your answer.

3 0

3 years ago

he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w

stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666 )

Step-by-step explanation:

Given the data in the question;

Sample 1 Sample 2

x"₁ = 259.23 x"₂ = 365.12

s₁ = 34.713 s₂ = 48.297

n₁ = 5 n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

$S_p^2$ = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

$S_p^2$ = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

$S_p^2$ = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [ 4 + 9 ]

$S_p^2$ = [ 4819.9692 + 20993.4 ] / [ 13 ]

$S_p^2$ = 25813.3692 / 13

$S_p^2$ = 1985.64378

Now the Standard Error will be;

$S_{x1-x2$ = √[ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

$S_{x1-x2$ = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

$S_{x1-x2$ = √[ 397.128756 + 198.564378 ]

$S_{x1-x2$ = √595.693134

$S_{x1-x2$ = 24.4068

Critical Value = $t_{\frac{\alpha }{2}, df$ = $t_{0.05, df=13$ = 1.771 { t-table }

So,

Margin of Error E = $t_{\frac{\alpha }{2}, df$ × [ ( $S_p^2$ / n₁ ) + ( $S_p^2$ / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666 )

3 0

3 years ago