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ruslelena [56]
2 years ago
11

Select the correct answer.

Mathematics
1 answer:
Sati [7]2 years ago
4 0

The given quadratic equation gives the parameters of the shape of the

graph of the equation.

  • The graph that is most likely associated with the model is; <u>graph B</u>

Reasons:

The given function is <u>n(t) = -2.82·t² + 25.74·t + 60.87</u>

by analyzing the above function, we have;

At t = 0

n(0) = -2.82 × 0² + 25.74 × 0 + 60.87 = 60.87

  • The x-coordinate of the maximum point is given by \displaystyle x = -\frac{b}{2 \cdot a}

Which gives;

\displaystyle t = -\frac{25.74}{2 \times (-2.82)} \approx 4.564

The maximum value of the function is therefore;

n(4.564) = -2.82 × 4.564² + 25.74 × 4.564 + 60.87 ≈ 119.61

The characteristics of the equation are;

Initial value of equation = 60.87

t-coordinate of the maximum point, t ≈ 4.564

Maximum value of the of the function = 119.61

By comparing with the given graphs, we have;

  • \begin{tabular}{c|c|c|}&Graph A&Graph B\\Initial value&100&75\\t-value at max point&7&4\\Maximum value&200&125\end{array}\right]

Therefore, the graph that will most likely be associated with the model is; <u>graph </u><u><em>B</em></u>.

Learn more about graphs of quadratic equations here:

brainly.com/question/10989920

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<h3>Answer: Choice D) </h3>

Work Shown:

(f+g)(x) = f(x)+g(x)\\\\(f+g)(x) = \frac{x-23}{x^2+9x-36}+\frac{1}{x+12}\\\\(f+g)(x) = \frac{x-23}{(x+12)(x-3)}+\frac{1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+1(x-3)}{(x+12)(x-3)}\\\\(f+g)(x) = \frac{x-23+x-3}{x^2+9x-36}\\\\(f+g)(x) = \frac{2x-26}{x^2+9x-36}\\\\

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