What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?
1 answer:
x^2 + 6xy + 8y2
4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
Combine like terms:
= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2
= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)
= -x^2 + 6xy + 8y^2
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Answer:
14/33
Step-by-step explanation:
-15.18 is the answer and you have added a = sign by mistake
I don't know, but I think we/you have to divide 5 into 6. If it is wrong, then i'm so sorry.
