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Tresset [83]
2 years ago
8

What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?

Mathematics
1 answer:
erica [24]2 years ago
5 0

x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)

= -x^2 + 6xy + 8y^2

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galben [10]

Answer:

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Step-by-step explanation:

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3 years ago
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3 years ago
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Step-by-step explanation:

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2 years ago
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saul85 [17]

Answer:

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4 0
3 years ago
Read 2 more answers
Use the discriminant to determine the number and type of solutions the equation has.
lidiya [134]
Discriminant = square root (b^2 -4*a*c)
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Therefore it has 2 rational soltions


4 0
3 years ago
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