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Tresset [83]
2 years ago
8

What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?

Mathematics
1 answer:
erica [24]2 years ago
5 0

x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)

= -x^2 + 6xy + 8y^2

You might be interested in
Which of these numbers is a prime number: 1, 11, 21, 51?
statuscvo [17]

Answer:

11 and 51

Step-by-step explanation:

1 technically isn't a prime since a prime can only be divided by two things (itself and 1) and 1 can only be divided by 1.

21 can be divided by 1, 3, 7, and 21 so it is not prime.

Hope this helps!

5 0
3 years ago
Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a
Zielflug [23.3K]

Answer:

The area of the associated sector is \frac{25}{24}\pi \ in^{2}  

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=5\pi\ in

substitute and solve for r

5\pi=2\pi r

r=2.5\ in

step 2

Find the area of the circle

we know that

The area of the circle is equal to

A=\pi r^{2}

we have

r=2.5\ in

substitute

A=\pi (2.5^{2})=6.25\pi\ in^{2}

step 3

Find the area of the associated sector

we know that

2\pi\ radians subtends the complete circle of area 6.25\pi\ in^{2}

so

by proportion

Find the area of a sector with a central angle of \pi/3\ radians

\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}

8 0
3 years ago
Clare has a set of cubes with a volume of 1 cm³ each. She also has a box with a volume of 24 cm³. Exactly two layers of cubes ca
Damm [24]

Answer:

12 cubes

Step-by-step explanation:

If the total volume of the box is 24 cm³ and the volume of each cube is 1 cm³ then that means that 24 total cubes can fit perfectly inside the box. Since there can only be two layers of cubes then we simply need to divide the total amount of cubes that will fit in the box by 2 to find the number of cubes in each layer...

24 / 2 = 12 cubes

Finally, we can see that each layer within the box will contain 12 cubes

5 0
2 years ago
Find the value(s) of x where the tangent to the graph of y=e^5x is parallel to the
Alik [6]

Answer:

There are none.

Step-by-step explanation:

<u>No calculus involved:</u>

The line, in slope-intercept form, has equation y=-10x+17, ie is always decreasing (easy to spot applying the definition)

Meanwhile, y=e^{5x} is always increasing over its domain.

At no point the tangent will be decreasing.

<u>Let's use calculus</u>

We are to solve the equation y'(x) = -10 \rightarrow 5e^{5x} = -10 \rightarrow e^{5x}=-2 which has no real solutions.

8 0
2 years ago
Help I’m almost out of time
VladimirAG [237]

Answer: First option.

Step-by-step explanation:

You can idenfity in the figure that \angle FCE is formed by two secants that intersect outside of the given circle.

It is important to remember that, by definition:

 Angle\ formed\ by\ two\ Secants=\frac{1}{2}( Difference\ of\ intercepted\ Arcs)

Knowing this, you can set up the following equation:

m\angle FCE=\frac{1}{2}(BD-FE)

Therefore, you must substitute values into the equation and then evaluate, in order to find the measure of the angle \angle FCE.

This is:

m\angle FCE=\frac{1}{2}(112\°-38\°)\\\\m\angle FCE=37\°

6 0
2 years ago
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