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Tresset [83]
3 years ago
8

What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?

Mathematics
1 answer:
erica [24]3 years ago
5 0

x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)

= -x^2 + 6xy + 8y^2

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  (-2.2, -1.6), (3, 1)

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Use the first equation to write an expression for x, then substitute that into the second equation:

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