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Tresset [83]
2 years ago
8

What is the result of subtracting 4x^2 + 3xy +2y^2 from 5x^2 + 3xy + 6y^2?

Mathematics
1 answer:
erica [24]2 years ago
5 0

x^2 + 6xy + 8y2

4x^2 + 3xy + 2y^2 - 5x^2 + 2xy + 6y^2

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

Combine like terms:

= 4x^2 + 3xy + 2y^2 + -5x^2 + 3xy + 6y^2

= (4x^2 + -5x^2) + (3xy + 3xy) + (2y^2 + 6y^2)

= -x^2 + 6xy + 8y^2

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On a floor plan for Rosedale Middle School, 1 inch represents 10 feet. If Sarah's classroom is 2 inches by 3 inches on the floor
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What is the slope of the line shown below? <br><br> A. 2<br> B. -1/2<br> C. -8/5<br> D. -2
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Solve for x; 7x + 9 = 2(4x + 2) Please show your work, will vote for the brainiest answer.
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5 0
2 years ago
A bicycle wheel with diameter 16 inches rides over a screw in the street. the screw is on level ground before it punctures the b
weqwewe [10]

The height of the screw = 16 inches.

<h3>How do you determine the number of revolutions in a circle?</h3>

The total distance covered in one revolution will be equal to the perimeter of the wheel. Finally, to find the total number of revolutions, divide the total distance by distance covered in one revolution.

Given that,

Diameter of a bicycle = 16 inches

The distance the bike moves (forward) after the screw punctures the tire = 56π inches

We note that the circumference of the bicycle = π·D = π × 16 = 16π inches

Therefore,

\frac{56\pi }{16\pi } = 3.5

Showing that the bicycle moves three and half complete turns (revolution) where after each complete turn, the screw starts from the bottom of the tire.

The height, h of the screw in the final half turn is given by the relation;

h = A cos(Bx - C) + D

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C = Phase shift = π

D = The mid line = Diameter/2 = 8 inches

Therefore;

h = 8×cos(π - π) + 8 = 16 inches

Hence, After the bike moves forward another 56π inches the height of the screw = 16 inches.

To learn more about number of revolution from the given link:

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