6 eggs (i think)
5x12=60 cookies require 2 eggs
30x12=360
360 divided by 60= 6
so six eggs
Answer:
x=2 and y=7
Step-by-step explanation:
Step: Solvey=2x+3for y:
y=2x+3
Step: Substitute2x+3foryiny=3x+1:
y=3x+1
2x+3=3x+1
2x+3+−3x=3x+1+−3x(Add -3x to both sides)
−x+3=1
−x+3+−3=1+−3(Add -3 to both sides)
−x=−2
−x
−1
=
−2
−1
(Divide both sides by -1)
x=2
Step: Substitute2forxiny=2x+3:
y=2x+3
y=(2)(2)+3
y=7(Simplify both sides of the equation)
Answer:
21 consonant tiles
Step-by-step explanation:
Henry has a bag containing 39 letter tiles, some consonants, and some vowels.
He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Step 1
We add up the number of tiles that he pulls out of the bag
= 7 consonant tiles + 6 vowel tiles
= 13 tiles
Step 2
We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag
= 39 tiles ÷ 13 tiles
= 3
Step 3
The most likely number of consonant tiles in Henry's bag is calculated as:
3 × The number of consonant tiles that was pulled out of the bag.
Hence:
3 × 7 consonant tiles
= 21 consonant tiles.
Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
The method of successive differences uses subtraction to the one number to the next and the process goes on until the difference settles constant which is not equal to zero. In this case, the constant difference reaches 25. Reversing the process to get the next term, the answer is 2509.
