A normal distribution is observed from the number of rentals per week for a certain car rental company. If the mean is 15 rental
1 answer:
The probability that on a randomly selected week, the car company rented greater than 24 rentals is 0.4987
First, we need to calculate the z-score using the formula;
where:
is the mean value = 15
is the standard deviation = 3
- x = 24
Substitute the given values into the formula to get the z-score
Checking the probability table for P(x > 3.000), the probability that on a randomly selected week, the car company rented greater than 24 rentals
is 0.4987
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Answer:
Step-by-step explanation:
This is your exponential growth function for population:
and these are your initial conditions with the year 2000 being t = 0
(0, 6.31) and (69, 12)
We will use those values to find the equation that models this population growth. In the coordinates, the first number is the time in years, t; the second number is the population after a certain time t goes by. In other words, the second number represents the A in our model. Using those values from the first set of coordinates will help us solve for A₀:
which is basically e raised to the power of 0 which is equal to 1, so we get from that first set of coordinates that A₀ = 6.31
Now we will use that along with the numbers in the second coordinate pair to find the value for k:
Begin by dividing both sides by 6.31 to get
and take the natural log of both sides since natural logs and e's undo each other:
Simplifying both sides give us:
.6427709734 = 69k so
k = .0093155
Now we can finally write the equation that models this population as
and we can answer the question about which year, x, will the population be 7 million, A.
Begin by dividing both sides by 6.31 to get
and again take the natural log of both sides:
and simplify to
.1037744728=.0093155t so
t ≈ 11
That means that in the year 2011 the population will be 7 million