Answer:
222 fence posts
Step-by-step explanation:
Since the log is 20 m long, correct to the nearest metre and has to be cut into fence posts which must be 90 cm long, correct to the nearest 10 centimetres, there can be x fence posts 90 cm long.
So, we have x × 90 cm = 20 m
x × 0.9 m = 20 m
x = 20 m/0.9 m
x = 222.22
x ≅ 222 fence posts
So, the largest number of fence posts that can possibly be cut from the log is 222 fence posts.
-2(x+9)-6=-24
-2x-18-6=-24
2x=0
x=0
2(x+9)-6=-24
2x+18-6=-24
2x=-36
x=-18
We will be using the formulas:
speed=distance/time
time=distance/speed
distance=speed×time
First let's find out Diane's rate of swimming. We can measure this by finding the slope (y/x) of a given coordinate on the graph. One point is (10,15), so you do 15/10=1.5m/s
Now for Rick's rate of swimming, just take a pair of values from the table. 12.5/10=1.25m/s
By the way m/s is metres per second for this
So at a constant speed of 1.5m/s, Diane swam 150m in 150/1.5= 100 seconds, or 1 minute 40 seconds
And at a constant speed of 1.25m/s, Rick swam 150m in 150/1.25= 120 seconds, or 2 minutes.
So the difference between their two times is 20 seconds
Answer:
200 kg
Step-by-step explanation:
First hour he sold 15% <em>(remaining is 85%)</em>
Second hour he sold 20% of remaining <em>(which is 85%)</em> -- so he sold 
, which is 17% (remaining 85-17=68%)
Third hour he sold 25% of remaining <em>(which is 68%)</em> -- so he sold 
, which is 17%
In third hour he sold 34, so 17% is 34. To find total he initially had, we need to find (100%). We can setup the ratio (letting x equal his initial amount):
Initially the farm stand owner had 200 kg of apples.
You can see that 2 sides are equal and the angle between these 2 sides So its SAS
