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o-na [289]
3 years ago
14

Which expression is equivalent to 3 2 times 3-5 ?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

A)

Step-by-step explanation:

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Which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21?
zmey [24]
We must plugin values:
3(7)-4(0)=21, is CORRECT since 7•3 is 21 and -4•0 is 0
3(11)-4(3)=21 is CORRECT since 3•11=33 and -4•3=-12 so 33-12=21
3(-3)-4(3)=21 is INCORRECT since 3•-3 is -9 and -4•3 is -12, -9-12 is -21
3(-1)-4(-6)=21 is CORRECT since 3•-1 is -3 and -4•-6 is 24 and so 24-3=21
4 0
4 years ago
Read 2 more answers
What is the derivative of ln(lnx^3)
chubhunter [2.5K]

the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , ln(lnx^3) , Let's differentiate it w.r.t x :

⇒ \frac{d(ln(lnx^3))}{dx}

Let lnx^3 = u

⇒ \frac{d(ln(u))}{dx}

⇒ \frac{1}{u} (\frac{d(u)}{dx} )

⇒ \frac{1}{u} (\frac{d(ln(x^3))}{dx} )

Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

⇒ 3x^2(\frac{1}{u})(\frac{1}{v} )

Putting value of u & v we get:

⇒ 3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )

⇒ \frac{3}{x(lnx^3)}    { lnx^n = n(lnx)  }

⇒ \frac{3}{3x(lnx)}

⇒ \frac{1}{x(lnx)}

Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

6 0
3 years ago
Please help me! I’m struggling so much: x-3y=3 2x+9y=11 (please find x and y plot points ill give brainliest!!)
Basile [38]

Answer:

CORRECT AMONDO

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I need some help please!
Lana71 [14]

Answer:

MP = 22.4 / 2 = 11.2

Step-by-step explanation:

If P is the center of the circle, then TN is the diameter of the circle and MP is the radius.

The formula for Diameter = 2 x radius

So Radius MP = Diameter / 2 = 22.4 / 2 = 11.2

5 0
3 years ago
Find the circumference of this circle<br>c,d,a,g,be​
zheka24 [161]

A,G,B

IDK I think thats it

4 0
3 years ago
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