Answer: range= 26, variance= 80 and standard deviation= 8.94
Step-by-step explanation:
Range = highest - lowest
Range = 146 - 120
Range= 26
Let m be mean
M=mean=sum/n
Mean=(120+134+146+127+138+133) / 6
M=798/6
M=133
The standard deviation sample formula:
S.D = sqrt( Summation of |x-m|^2 / n-1)
Let start finding:
|x-m|^2
For 1st: |120-133|^2=169
For 2nd: |134-133|^2=1
For 3rd: |146-133|^2=169
For 4th: |127-133|^2=36
For 5th: |138-133|^2=25
For 6th: |133-133|^2=0
Summation of |x-m|^2 = 400
The standard deviation formula is :
S.D = sqrt( Summation of |x-m|^2 / n-1)
S.D= sqrt(400 / 5)
S.D=sqrt(80)
S.D= 8.94
Variance = (Summation of |x-m|^2 / n-1)
Variance= 400/5
Variance= 80
The answer is y= 3/4x - 4.
Answer:
The answer is 5 students.
Step-by-step explanation:
This problem is a division problem.
To solve, divide 4 by 4/5.
There is a strategy for this- Keep, Change, Flip.
Keep the dividend like it is, which is 4 or 4/1.
Change the division to multiplication.
And flip the divisor- 4/5 to 5/4.
When you multiply, you should get 20/4.
Simplify by dividing 20 by 4.
20 divided by 4 is 5.
So the answer is 5 students
QUESTION 1
The given inequality is

We group like terms to get,

This implies that,
or
.
We simplify the inequality to get,
or
.
We can write this interval notation to get,
.
QUESTION 2
.
We group like terms to get,
.

We split the absolute value sign to get,
or 
This implies that,
or 
or 
or 
We can write this interval notation to get,
.
QUESTION 3
The given inequality is

We split the absolute value sign to obtain,
or 
This simplifies to
and 
and 
and 
and 

We write this in interval form to get,
![[-\frac{10}{3},2]](https://tex.z-dn.net/?f=%5B-%5Cfrac%7B10%7D%7B3%7D%2C2%5D)
QUESTION 4
The given inequality is

We split the absolute value sign to get,
or 
This simplifies to,
or 
This implies that,
or 
or 
or 
We write this in interval notation to get,

Answer:
I don't think any are a correct graph of the function. But here are the ordered pairs. (1,0),(0,-2),(-1,-4)
Step-by-step explanation:
Take three values for x and plug them in for your y's. For instance x values of 1,0,-1. Plug each in to find the y value. 2(1) - 2 =y so (1,0)