Ask question

Ask question

All categories

3 years ago

15

If sin(theta°) = 0.5, and we know that cos (theta°) < 0, then what is the smallest possible positive value of theta?

1 answer:

9966 [12]3 years ago

4 0

Answer:

150°

Step-by-step explanation:

It is given that CosФ < 0 i.e CosФ is negative.

Therefore, the minimum the value of Ф for which CosФ <0 will be in the second quadrant i.e 90° < Ф < 180°.

Now it is also given that, Sin Ф =0.5 {the value of SinФ is positive because Sin value is positive in second quadrant.}

⇒ Ф =180° - Sin⁻¹ (0.5) = 180°-30° =150° (Answer)

You might be interested in

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

mixer [17]

Answer: range= 26, variance= 80 and standard deviation= 8.94

Step-by-step explanation:

Range = highest - lowest

Range = 146 - 120

Range= 26

Let m be mean

M=mean=sum/n

Mean=(120+134+146+127+138+133) / 6

M=798/6

M=133

The standard deviation sample formula:

S.D = sqrt( Summation of |x-m|^2 / n-1)

Let start finding:

|x-m|^2

For 1st: |120-133|^2=169

For 2nd: |134-133|^2=1

For 3rd: |146-133|^2=169

For 4th: |127-133|^2=36

For 5th: |138-133|^2=25

For 6th: |133-133|^2=0

Summation of |x-m|^2 = 400

The standard deviation formula is :

S.D = sqrt( Summation of |x-m|^2 / n-1)

S.D= sqrt(400 / 5)

S.D=sqrt(80)

S.D= 8.94

Variance = (Summation of |x-m|^2 / n-1)

Variance= 400/5

Variance= 80

3 0

3 years ago

Read 2 more answers

Please please please

lapo4ka [179]

The answer is y= 3/4x - 4.

6 0

3 years ago

one teacher want to give each student 4/5 of a slice of pizza, if the teacher has 4 slices of pizza, then how many students will

GuDViN [60]

Answer:

The answer is 5 students.

Step-by-step explanation:

This problem is a division problem.

To solve, divide 4 by 4/5.

There is a strategy for this- Keep, Change, Flip.

Keep the dividend like it is, which is 4 or 4/1.

Change the division to multiplication.

And flip the divisor- 4/5 to 5/4.

When you multiply, you should get 20/4.

Simplify by dividing 20 by 4.

20 divided by 4 is 5.

So the answer is 5 students

6 0

3 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

2 years ago

Can someone help me out how to work on this.

enyata [817]

Answer:

I don't think any are a correct graph of the function. But here are the ordered pairs. (1,0),(0,-2),(-1,-4)

Step-by-step explanation:

Take three values for x and plug them in for your y's. For instance x values of 1,0,-1. Plug each in to find the y value. 2(1) - 2 =y so (1,0)

3 0

3 years ago

Read 2 more answers