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Natalka [10]
3 years ago
15

If sin(theta°) = 0.5, and we know that cos (theta°) < 0, then what is the smallest possible positive value of theta?

Mathematics
1 answer:
9966 [12]3 years ago
4 0

Answer:

150°

Step-by-step explanation:

It is given that CosФ < 0 i.e CosФ is negative.

Therefore, the minimum the value of Ф for which CosФ <0 will be in the second quadrant i.e 90° < Ф < 180°.

Now it is also given that, Sin Ф =0.5 {the value of SinФ is positive because Sin value is positive in second quadrant.}

⇒ Ф =180° - Sin⁻¹ (0.5) = 180°-30° =150° (Answer)

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Let A = {1, 2, 3, 4, 5} and B = {2, 4}. What is A ∩ B? (1 point)
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Answer:

{2, 4}.

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3 years ago
How do i do this?????????
Gnom [1K]

Answer:

x≥5

Step-by-step explanation:

-1 ≥ x/-5

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I'm not sure but I tried.

For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.

8 0
2 years ago
Write an equation for each line in slope-intercept form.
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Answer:

y = x + 7

Step-by-step explanation:

The slope-intercept form of a line is:

y = mx + b

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Looking at the graph, we can see that the line intersects the y-axis at y = 7. So 7 would be our y-intercept.

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3 years ago
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