Answer:
The correct answer to the following question will be Error-detection.
Explanation:
Error-detection: The detection of errors caused during the transmission from the transmitter to the receiver by damage and other noises, known as Error-detection. This error-detection has the ability to resolute if something went wrong and if any error occurs in the program.
There are mainly three types of error-detection, these types can be followed:
- Automatic Repeat Request (ARQ)
- Forward Error Correction
- Hybrid Schemes
There are two methods for error-detection, such as:
- Single parity check
- Two-dimensional parity check
Answer:
batch sequence check.
Explanation:
A batch sequence check can be defined as a strategic and systematic control plan which typically involves the process of inputting a range of numbers comprising a batch and then inputting each serially numbered document.
The steps for checking an event data within a batch using a batch sequence check include the following;
I. You'll enter a range of serial numbers of the document in a batch.
II. You'll enter each serially pre-numbered document one after the other.
III. The input documents are sorted by a computer into a serial (numerical) order, match the sequence number range against the input documents, and then reports any part of the document that is missing, a duplicate and out of range.
You shood just be able to tern it on
Answer:
Explanation:
In MATLAB, the following command:
Performs the element by elemet division of A and B. This comand is called Right-array division.
So, in your case, we could divide A by B element by element, only using fully-vectorised code (ie. no loops), with the following code:
![a = [2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 33 34 35 36 37 38 39 40];b = [1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 43 45 47 49 50 54 59 60];C = a./b](https://tex.z-dn.net/?f=a%20%3D%20%5B2%204%206%208%2010%2012%2014%2016%2018%2020%2022%2024%2026%2028%2030%2032%2033%2034%2035%2036%2037%2038%2039%2040%5D%3B%3C%2Fp%3E%3Cp%3Eb%20%3D%20%5B1%203%205%207%209%2011%2013%2015%2017%2019%2021%2023%2025%2027%2029%2031%2033%2043%2045%2047%2049%2050%2054%2059%2060%5D%3B%3C%2Fp%3E%3Cp%3EC%20%3D%20a.%2Fb)
;
C would be the element by element division of A and B, with no loops.
