Answer:
emmm nose ponga lo en español para ayudarles
Answer: Since the second differences are constant, there is a quadratic relationship between and .
Step-by-step explanation:
(x, y) = ( cos 45, sin 45) =
![=\text{ (}\frac{\sqrt[]{2}}{2}\text{ , }\frac{\sqrt[]{2}}{2}\text{ )}](https://tex.z-dn.net/?f=%3D%5Ctext%7B%20%28%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%2C%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%29%7D)
The correct option is A
Answer:
<em>71.6 degrees </em>
Step-by-step explanation:
The formula for calculating the angle between two vectors is expressed as;
u.v = |u||v|cos theta
u.v = (8, 4).(9, -9)
u.v = 8(9)+4(-9)
u.v = 72-36
u.v = 36
|u| = √8²+4²
|u| = √64+16
|u| = √80
|v| = √9²+(-9)²
|v| = √81+81
|v| = √162
36 = √80*√162 cos theta
36 = √12960 cos theta
36 = 113.84 cos theta
cos theta = 36/113.84
cos theta = 36/113.84
cos theta = 0.3162
theta = arccos (0.3162)
<em>theta = 71.6 degrees </em>
<em>Hence the angle between the given vectors is 71.6 degrees </em>
5.95 + 2.95 = 8.9
8.9 + 29.95 = 38.85
62.35 - 38.85 = 23.5
So Daniel spent $23.50 on long distance calling
