Assuming that the actual question reads lines b and c are perpendicular to line d
we are given that c is perpendicular to line d and parallel to line a. Since b is also perpendicular to line d, a b and c must all be parallel (draw it out will make a lot more sense)
So b is also parallel to line a
Answer:I'm not sure but I think it's 47.38
Step-by-step explanation:
Answer:
120
Step-by-step explanation:
3*30=90
1*30=30
90+30=120
Answer:
²
Step-by-step explanation:
Given,
f ( θ ) = tan θ + sec θ
g ( θ ) = cosθ/1-sinθ
To prove : -
f ( θ ) = g ( θ )
Proof : -
LHS = f ( θ )
RHS = g ( θ )
LHS
= f ( θ )
= tan θ + sec θ
{ Identities : -
tan θ = sin θ/cos θ
sec θ = 1/cos θ }
= sin θ/cos θ + 1/cos θ
= ( sin θ + 1 )/cos θ
= ( 1 + sin θ )/cos θ
Multiply ( 1 - sin θ ) to both numerator and denominator,
= ( 1 + sin θ ) ( 1 - sin θ ) / ( cos θ ) ( 1 - sin θ )
{ ( 1 + sin θ ) ( 1 - sin θ ) is in the form a² - b² Identity,
so,
( 1 + sin θ ) ( 1 - sin θ ) = 1² - sin²θ = 1 - sin²θ
Formula : -
sin²θ + cos²θ = 1
cos²θ = 1 - sin²θ
So,
1 - sin²θ = cos²θ }
= cos²θ / ( cos θ ) ( 1 - sin θ )
{ cos²θ = cos θ . cos θ }
= cos θ . cos θ / ( cos θ ) ( 1 - sin θ )
= cos θ / 1 - sin θ
= RHS
= g ( θ )
Hence proved.