30 students in Mr. Smith’s class, 7
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
We can write sq root (- 18) as = sq root [3 x 3 x (-2)]
Similarly sq root ( - 8) = sq root [2 x 2 x (-2)]
2 sq root [2 x 2 x (-2)] - 3 sq root [3 x 3 x(-2)]
We simply,
2 x2 sq root (-2) - 3 x 3 sq root (-3)
4 sq root (-2) - 9 sq root (-2)
Bcoz sq root (-2) is common in bot term so
So
Sq root (-2) (4-9)
-5 sq root (-2) answer
Answer:
This contradicts the Mean Value Theorem since there exists a c on (1, 7) such that f '(c) = f(7) − f(1) (7 − 1) , but f is not continuous at x = 3
Step-by-step explanation:
The given function is
When we differentiate this function with respect to x, we get;
We want to find all values of c in (1,7) such that f(7) − f(1) = f '(c)(7 − 1)
This implies that;
If this function satisfies the Mean Value Theorem, then f must be continuous on [1,7] and differentiable on (1,7).
But f is not continuous at x=3, hence this hypothesis of the Mean Value Theorem is contradicted.
Answer:
your answers are going to be
Step-by-step explanation:
hope it helps have a nice day!!