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xxTIMURxx [149]
2 years ago
9

X^2+3x-10 will be zero when x equals

Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Answer:

This is a polynomial of second class degree. So using quadratic equation

x is 2 and negative 5

Anit [1.1K]2 years ago
3 0

Answer:

Answer: x equals to 2 and -5

Step-by-step explanation:

{ \tt{ {x}^{2} + 3x - 10 = 0 }}

» Factorise the equation quadratically:

{ \tt{(x - 2)(x + 5) = 0}} \\ { \tt{x = 2 \:  \: and \:  \:  - 5}}

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viva [34]

Answer:

The answer to this question is 6720

6 0
2 years ago
Solve the equation 5.4g + 4 = 1.4g +20.
katovenus [111]
A. g=4
b. first you're going to subtract 1.4g from both sides;
5.4g + 4 - 1.4g = 1.4g + 20 - 1.4g
then simplify it;
4g+4=20
then, you'll subtract 4 from both sides;
4g + 4 - 4 = 20 - 4
then simplify again;
4g=16
lastly, you will divide 4 from both sides;
4g/4 = 16/4
since 16/4=4, then g=4
5 0
3 years ago
An important factor in selling a residential property is the number of times real estate agents show a home. A sample of 23 home
yanalaym [24]

Using the t-distribution, it is found that:

a. The <u>margin of error</u> is of 4.7 homes.

b. The 98% confidence interval for the population mean is (19.3, 28.7).

The information given in the text is:

  • Sample mean of \overline{x} = 24.
  • Sample standard deviation of s = 9.
  • Sample size of n = 23.

We are given the <u>standard deviation for the sample</u>, which is why the t-distribution is used to solve this question.

The confidence interval is:

\overline{x} \pm M

The margin of error is:

M = t\frac{s}{\sqrt{n}}

Item a:

The critical value, using a t-distribution calculator, for a two-tailed <u>98% confidence interval</u>, with 23 - 1 = <u>22 df</u>, is t = 2.508.

Then, the <em>margin of error</em> is:

M = t\frac{s}{\sqrt{n}} = 2.508\frac{9}{\sqrt{23}} = 4.7

Item b:

The interval is:

\overline{x} - M = 24 - 4.7 = 19.3

\overline{x} + M = 24 + 4.7 = 28.7

The 98% confidence interval for the population mean is (19.3, 28.7).

A similar problem is given at brainly.com/question/15180581

3 0
2 years ago
Can someone confirm this? is it correct?
EastWind [94]
<span>60 Sorry, but the value of 150 you entered is incorrect. So let's find the correct value. The first thing to do is determine how large the Jefferson High School parking lot was originally. You could do that by adding up the area of 3 regions. They would be a 75x300 ft rectangle, a 75x165 ft rectangle, and a 75x75 ft square. But I'm lazy and another way to calculate that area is take the area of the (300+75)x(165+75) ft square (the sum of the old parking lot plus the area covered by the school) and subtract 300x165 (the area of the school). So (300+75)x(165+75) - 300x165 = 375x240 - 300x165 = 90000 - 49500 = 40500 So the old parking lot covers 40500 square feet. Since we want to double the area, the area that we'll get from the expansion will also be 40500 square feet. So let's setup an equation for that: (375+x)(240+x)-90000 = 40500 The values of 375, 240, and 90000 were gotten from the length and width of the old area covered and one of the intermediate results we calculated when we figured out the area of the old parking lot. Let's expand the equation: (375+x)(240+x)-90000 = 40500 x^2 + 375x + 240x + 90000 - 90000 = 40500 x^2 + 615x = 40500 x^2 + 615x - 40500 = 0 Now we have a normal quadratic equation. Let's use the quadratic formula to find its roots. They are: -675 and 60. Obviously they didn't shrink the area by 675 feet in both dimensions, so we can toss that root out. And the value of 60 makes sense. So the old parking lot was expanded by 60 feet in both dimensions.</span>
8 0
3 years ago
2) university theater sold 556 tickets for a play. tickets cost $22 per adultand $12 per senior citizen. if total receipts were
harina [27]
About 708 or 707.6666666667
7 0
2 years ago
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