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1 year ago

X^2+3x-10 will be zero when x equals

Mathematics

2 answers:

Flauer [41]1 year ago

8 0

Answer:

This is a polynomial of second class degree. So using quadratic equation

x is 2 and negative 5

Anit [1.1K]1 year ago

3 0

Answer:

Answer: x equals to 2 and -5

Step-by-step explanation:

${ \tt{ {x}^{2} + 3x - 10 = 0 }}$

» Factorise the equation quadratically:

${ \tt{(x - 2)(x + 5) = 0}} \\ { \tt{x = 2 \: \: and \: \: - 5}}$

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PLS HELP ME THIS IS HARD

SOVA2 [1]

Answer:

1 dollar is equal to 0.75 E

Step-by-step explanation:

120$ = 90 e -----> 4$ = 3E

250$ = 187.50 e -----> 4$ = 3E

400$ = 300 e -----> 4$ = 3E

----------------------------------

from this we know 4$ = 3E

1 E = 4$/3

1 E = 1.33...$

---------------------

1 $ = 3/4 E

1 $ = 0.75 E

---------------------

1.33...$ dollars is equal to 1 E and

1 $ is equal to 0.75 E

-----------------------------------

90 x 1.33... =120

187.50x1.33...= 250

300 x 1.33... = 400

--------------------------

4 0

2 years ago

The table shows the values of a function f(x).

QveST [7]

Answer:

The average rate of change is $=-4$

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is given by;

$=\frac{f(b)-f(a)}{b-a}$

We want to find the average rate of change of the function represented in the table from x=-2 to x=2.

$=\frac{f(2)-f(-2)}{2--2}$

From the table f(-2)=25 and f(2)=9

The average rate of change from x=-2 to x=2 is

$=\frac{9-25}{2--2}$

$=\frac{-16}{4}$

$=-4$

3 0

2 years ago

For a given function ƒ(x) = x2 – x + 1, the operation –ƒ(x) = –(x2 – x + 1) will result in a

Mekhanik [1.2K]

Given:

The function is:

$f(x)=x^2-x+1$

To find:

The result of the operation $-f(x)=-(x^2-x+1)$ .

Solution:

If $g(x)=-f(x)$ , then the graph of f(x) is reflected across the x-axis to get the graph of g(x).

We have,

$f(x)=x^2-x+1$

The given operation is:

$-f(x)=-(x^2-x+1)$

So, it will result in a reflection across the x-axis.

Therefore, the correct option is A.

4 0

2 years ago

HURRY PLZ! also please find tan as well!!! will mark brainliest!!

vazorg [7]

I honestly don’t know man but don’t worry, if you get a bad score it won’t matter in 30 years :)

3 0

2 years ago

If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?

irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV