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Darina [25.2K]
2 years ago
9

Find the value of x.

Mathematics
2 answers:
Snezhnost [94]2 years ago
6 0
X=19 hope this helps
tatiyna2 years ago
4 0

Answer:

x = 19

Step-by-step explanation:

(5x+4)+(x-2)+(3x+7) = 180

5x+4+x-2+3x+7 = 180

9x+9 = 180

9x = 171

x = 171/9

x = 19

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<em>Step 1: Keep variable on one side, and subtract 13 on both sides.</em>

b > 21

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<em>Step 3: Since it is not "or equal too" we will use an open dot, since we do not contain that point. Put dot over 21. </em>

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<em>Step 4: The sign is ( > ) meaning greater than. Therefore all points greater than 21 is </em><em>true</em><em>. See graph. </em>

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This graph represents a linear function. Enter an equation in the form y = mx + b that represents the function.
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Step-by-step explanation:

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3 years ago
Please help!!!!!!!!!!!!!!!!!!
elena55 [62]

h(x)=(f\circ g)(x)\\\\h(x)=\sqrt[3]{x+3};\ f(x)=\sqrt[3]{x+2}\\\\h(x)=\sqrt[3]{x+1+2}=\sqrt[3]{(x+1)+2}=\sqrt[3]{g(x)+2}\to \boxed{g(x)=x+1}

-----------------------------------------------------------------------------------------------

f(x)=2x;\ g(x)=2x-1;\ h(x)=\sqrt{x}\\\\(f\circ g\circ h)(9)=?\\\\h(9)=\sqrt9=3\\\\(g\circ h)(9)=g(3)=2(3)-1=6-1=5\\\\(f\circ g\circ h)(9)=f(5)=2(5)=10\\------------------------------\\other\ method:\\\\(f\circ g\circ h)(x)=2(2\sqrt{x}-1)=4\sqrt{x}-2\\\\(f\circ g\circ h)(9)=4\sqrt9-2=4(3)-2=12-2=10

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f(x)=4x+1;\ g(x)=x^2-5\\\\(f\circ g)(4)=?\\\\g(4)=4^2-5=16-5=11\\(f\circ g)(4)=f(11)=4(11)+1=44+1=45\\----------------------------------\\other\ method:\\\\(f\circ g)(x)=4(x^2-5)+1=4x^2-20+1=4x^2-19\\\\(f\circ g)(4)=4(4)^2-19=4(16)-19=64-19=45


8 0
3 years ago
HELP NOW!!!! thx :DDDD
Natali5045456 [20]

Answer:

the second one

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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